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Kobotan [32]
4 years ago
14

Solve The equation Pls i need this ASAP! y + (–6) = –9

Mathematics
2 answers:
omeli [17]4 years ago
7 0
Your question: Solve for y in <span>y + (–6) = –9
====================================================================
SOLVING...

y + (-6) = -9

Subtract -6 from each side
y + (-6) - (-6) = -9 - (-6)
y = -3
</span>
trapecia [35]4 years ago
3 0
Y-6=-9. Y=-9+6. Y=-3.
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I am having a test tomorrow about this can someone help me explain it?​
Amiraneli [1.4K]

Answer:

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Step-by-step explanation:

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145+72=217

7 0
3 years ago
Read 2 more answers
How to solve the system of equation 500y-600x=2800 , 400y-400x=2400 by elimination
tatiyna

Answer:

x=2 and y=8

Step-by-step explanation:

Given:

Equation 1:

500y-600x=2800

Simplifying the above equation by dividing both sides by 100

\frac{500y-600x}{100}=\frac{2800}{100}

\frac{500y}{100}-\frac{600x}{100}=28\\\\5y-6x=28

Equation 2:

400y-400x=2400

Simplifying the above equation by dividing both sides by 400.

\frac{400y-400x}{400}=\frac{2400}{400}

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Now the system of equation is:

(1a) 5y-6x=28

(2a) y-x=6

Solving by elimination

Multiplying equation (2a) with -5

-5(y-x)=-5\times 6

(2b) -5y+5x=-30

Adding equations (1a) and (2b) in order to eliminate y

      5y-6x=28

+  -5y+5x=-30

We get -x=-2

∴ x=2

Plugging x=2 in equation (2a).

y-2=6

Adding 2 both sides.

y-2+2=6+2

∴ y=8

7 0
3 years ago
What is an equation of the line that passes through the points (-1, 6) and<br> (-1, -5)?
lawyer [7]

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x = -1

Step-by-step explanation:

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3 years ago
A graph titled Marginal Cost of Bikes has the bike number of the x-axis, from 1 to 7, and marginal cost on the y-axis, from 0 to
aleksklad [387]

Answer:

80

20

50

60

Step-by-step explanation:

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4 0
3 years ago
Which is not an equation of the line going through (3,-6) and (1, 2)?
Olegator [25]

Answer:

○ \displaystyle y - 1 = -4(x - 2)

Step-by-step explanation:

When you plug these coordinates into this equation, they will be confirmed as <em>false</em>.

I am joyous to assist you anytime.

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3 years ago
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