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loris [4]
3 years ago
14

What is –3² + (2 – 6)(10) evaluated?

Mathematics
2 answers:
Levart [38]3 years ago
8 0
\bf -3^2+(2-6)(10)\implies \stackrel{\mathbb{PEMDAS}}{-3^2+(-4)(10)\implies -9+(-4)(10)}
\\\\\\
-9+(-40)\implies -9-40\implies -49
bagirrra123 [75]3 years ago
5 0
-3^2 + (2-6)(10) evaluated is -49
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Jerome, kevin and seth shared a submarine sandwhich. Jerome ate 1/2 of the sandwich , kevin ate 1/3 of the sandwich, and seth at
Paul [167]

Given:

Jerome ate 1/2 of the sandwich , Kevin ate 1/3 of the sandwich, and Seth ate the rest.

To find:

The ratio of jerome's share to kevin's share to seth's share.

Solution:

Jerome ate 1/2 of the sandwich. So,

Jerome's share = \dfrac{1}{2}

Kevin ate 1/3 of the sandwich. So,

Kevin's share = \dfrac{1}{3}

Seth ate the rest. So,

Seth's share = 1-\dfrac{1}{2}-\dfrac{1}{3}

                     = \dfrac{6-3-2}{6}

                    = \dfrac{1}{6}

The ratio of jerome's share to kevin's share to seth's share is:

\dfrac{1}{2}:\dfrac{1}{3}:\dfrac{1}{6}

To simplify the ratio multiply the ratio by 6.

\dfrac{1}{2}\times 6:\dfrac{1}{3}\times 6:\dfrac{1}{6}\times 6

3:2:1

Therefore, the ratio of jerome's share to kevin's share to seth's share is 3:2:1.

8 0
3 years ago
What is the measure of angle GXD?​
s2008m [1.1K]

Answer:

75 = GXD

Step-by-step explanation:

We know that CXE is a straight line

A straight line is 180 degrees

CXE = CXG + GXD +DXE

Substituting what we know

180 = 85+ GXD + 20

Combine like terms

180 = 105+GXD

Subtract 105 from each side

180-105 = 105-105 +GXD

75 = GXD

7 0
3 years ago
Galactic Rotation Speed. We are located about 27,000 light-years from the galactic center and we orbit the center about once eve
Alexxandr [17]

Answer:

speed = 796142.197 km/hr

Step-by-step explanation:

solution

we consider here orbit around galactic center is circular so

circumference formula will be here

circumference C = 2πr   ........1

here we know r = 27000

so

circumference C = 2 π × 27000

C = 169560 light year

so

we travel 169560 light year in 230000000 years

so distance will be

distance = \frac{169560}{230000000}

distance = 0.00073721 light year/year

and we know 1 year = 8760 hours

so 1 light year = 9.46027 ×10^{12} km

so

sped of moving is

speed = 0.00073721 × 9.46027 × \frac{10^{12}}{8760}  km/hr

speed = 796142.197 km/hr

5 0
4 years ago
Help me please I beg u
maxonik [38]
Divide the top number by the bottom number, then move decimal point to the right two spots .
4 0
4 years ago
What is a mean median and mode
Anarel [89]

Answer:

Mean, median, and mode are three kinds of "averages".

Step-by-step explanation:

Find the mean, median, mode, and range for the following list of values:

13, 18, 13, 14, 13, 16, 14, 21, 13

The mean is the usual average, so I'll add and then divide:

(13 + 18 + 13 + 14 + 13 + 16 + 14 + 21 + 13) ÷ 9 = 15

Note that the mean, in this case, isn't a value from the original list. This is a common result. You should not assume that your mean will be one of your original numbers.

The median is the middle value, so first I'll have to rewrite the list in numerical order:

13, 13, 13, 13, 14, 14, 16, 18, 21

There are nine numbers in the list, so the middle one will be the (9 + 1) ÷ 2 = 10 ÷ 2 = 5th number:

13, 13, 13, 13, 14, 14, 16, 18, 21

So the median is 14.

The mode is the number that is repeated more often than any other, so 13 is the mode.

The largest value in the list is 21, and the smallest is 13, so the range is 21 – 13 = 8.

mean: 15

median: 14

mode: 13

range: 8

4 0
4 years ago
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