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aalyn [17]
3 years ago
8

The longest side of a triangle is five more units than the shortest side. The third side is three times the length of the shorte

st side. If the perimeter of the triangle is 50 units, write and solve an equation to find the lengths of all three sides.
Write the equation below:

Shortest side:

Longer side:

Third side:
Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

shortest : 9

longer : 9 + 5 = 14

third : 3 x 9 = 27

Step-by-step explanation:

let a be the shortest side

shortest side : a

longer side : a + 5

third side: 3a

a + a + 5 +3a = 50

5a + 5 = 50

5a = 45

a = 9

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Given that WA = 5x – 8 and WC = 3x + 2, find WB. A. WB = 5 B. WB = 8 C. WB = 10 D. WB = 17
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The rest of the question is the attached figure.
============================================
Δ AYW a right triangle at Y ⇒⇒⇒ ∴ WA² = AY² + YW²
And AY = YB ⇒⇒⇒ ∴ WA² = YB² + YW²   → (1)
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Δ CXW a right triangle at Y ⇒⇒⇒ ∴ WC² = CX² + XW²
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Δ BXW a right triangle at Y ⇒⇒⇒ ∴ WB² = XB² + XW²  → (5)
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