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3 years ago

How much heat is contained in 100 kg of water at 60.0 °C?

1 answer:

6 0

First we need to write down heat capacity for water which is constant.
cp=4186 J/(kg*K)

The equation for Energy that we will be calculating is:

E=cp*m*T
where m is mass and T is absolute temperature (273,15 + 60 in this case). Replacing all the values in equation we get:

E = 4186*100*333,15 = 139 456 590 J

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A vertical, solid steel post 25 cm in diameter and 2.50m long is required to support a load of 8000kg. You can ignore the weight

Gwar [14]

(a) The stress in the post is 1,568,000 N/m²

(b) The strain in the post is 7.61 x 10⁻⁶

<h3>Area of the steel post</h3>

A = πd²/4

where;

d is the diameter

A = π(0.25²)/4 = 0.05 m²

<h3>Stress on the steel post</h3>

σ = F/A

σ = mg/A

where;

m is mass supported by the steel
g is acceleration due to gravity
A is the area of the steel post

σ = (8000 x 9.8)/(0.05)

σ = 1,568,000 N/m²

<h3>Strain of the post</h3>

E = stress / strain

where;

E is Young's modulus of steel = 206 Gpa

strain = stress/E

strain = (1,568,000) / (206 x 10⁹)

strain = 7.61 x 10⁻⁶

<h3>Change in length of the steel post</h3>

strain = ΔL/L

where;

ΔL is change in length
L is original length

ΔL = 7.61 x 10⁻⁶ x 2.5

ΔL = 1.9 x 10⁻⁵ m

Learn more about Young's modulus of steel here: brainly.com/question/14772333

#SPJ1

7 0

2 years ago

A road perpendicular to a highway leads to a farmhouse located 7 mile away. An automobile traveling on the highway passes throug

Fantom [35]

Answer:

The rate at which the automobile is moving away from the farmhouse is 27.29 m/h.

Explanation:

As shown in the figure, A denotes the position of farmhouse, B be the location of highway intersection and C be the direction along which automobile is moving.

Consider s be the distance between farmhouse and automobile which is represent by AC, x is the distance between intersection and automobile which is represent by BC and the distance between intersection of highway and automobile is represent by AB.

Applying Pythagoras Theorem to the figure,

(AB)² + (BC)² = (AC)²

Since, AB = 7 miles, BC = x and AC = s.

7² + x² = s²

Differentiating both sides of the above equation with respect to time :

$\frac{d}{dt}(7^{2} +x^{2} )=\frac{d}{dt}s^{2}$

$2x\frac{dx}{dt} = 2s\frac{ds}{dt}$

$\frac{x}{s}\frac{dx}{dt}=\frac{ds}{dt}$

$\frac{x}{\sqrt{7^{2}+x^{2} } }\frac{dx}{dt}=\frac{ds}{dt}$

When the automobile is 4 miles past the intersection, i.e.

x = 4 miles and $\frac{dx}{dt}$ = 55 m/h, then

$\frac{4}{\sqrt{7^{2}+4^{2} } }55=\frac{ds}{dt}$

$\frac{ds}{dt}=27.29$ m/h

3 0

3 years ago

Days when the sun’s light hits both hemispheres equally are called __________.

anyanavicka [17]

It is called an equinox. This days happen because the plane of the Earth's equator passes through the center of the Sun, in result, the light coming from it hits both hemispheres equally. Hopefully my answer has come to your help.

8 0

3 years ago

You push a desk with 230 N, but the desk doesn't move due to its friction with the ground. What is the magnitude of the friction

ASHA 777 [7]

Answer:

$force \: = friction \: based \: on \: newtons \: third \: law \\ \: f = |230| = 230 \: newton \\ this \: is \: why \: the \: desk \: \\ doesnt \: move...$

3 0

3 years ago

Name the processes of going (a) from a solid to a gas and (b) from a gas to a solid.

marissa [1.9K]

The answer to the first one is sublimation.

8 0

3 years ago