Answer:
The area of an octagon whose perimeter is 120 cm is 1086.4 
Step-by-step explanation:
An octagon is a polygon with eight sides. If the lengths of all the sides and the measurement of all the angles are equal, the octagon is called a regular octagon.
There is a predefined set of formulas for the calculation of perimeter, and area of a regular octagon.
The perimeter of an Octagon is given by
and the area of an Octagon is given by
We know that the perimeter is 120 cm, solving for side length (a) in the perimeter formula we get
Now, we calculate the area
Answer:
C. -5
Step-by-step explanation:
for g(x) =ax and f(x) = x, both are linear function. There is nothing to be upward or downward and both are lines nothing to compare its narrowness.
If g(x) = ax² vs f(x) = x²
Then a = -5 is the answer (-: downward and 5: vertical stretch)
Step-by-step explanation:
<u>Combine Like-Terms:</u>
-0.8m + 3 - 12.5m + 95.36m
-13.3m + 3 + 95.36m
82.06m + 3
82.06m + 3 is your simplified expression.
We are basically given most of what we need to calculate the height of the cannonball.
We use the formula h = –16t+ vt + s to find the height requested.
Let v = 160
Let s = 10
Let t = time in seconds
Was the value of t included? We need to know t to plug into our formula.
You know everything else except for t. Go back to your notes to search for t. Afterward, plug the value of t and everything else given above into the formula and calculate to find h.
5 (7) - 3 (-8)
35 - -24
Because two negatives equal a positive the subtraction sign will change into an addition sign.
35+24
So your answer will be 59.
Hope this helped :)
