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cupoosta [38]
3 years ago
7

Find the range of y = 3/2 cos 4x - 1

Mathematics
1 answer:
motikmotik3 years ago
5 0

Answer:

B. -2\frac{1}{2} \leq y \leq \frac{1}{2}

Step-by-step explanation:


The given trigonometric function is

f(x)=\frac{3}{2}cos4x-1.


The amplitude of this function is \frac{3}{2}, so under normal circumstances the range is supposed to be

-\frac{3}{2} \leq y \leq \frac{3}{2}

But the -1 is a downward vertical shift.

Therefore the normal boundaries  of the range will shift down one unit to give the range of the transformed function.


We subtract 1 from the lower boundary to get -\frac{3}{2}-1=-2\frac{1}{2}


We also subtract 1 from the upper boundary to get -frac{3}{2}-1=\frac{1}{2}


Hence the range is


-2\frac{1}{2} \leq y \leq \frac{1}{2}

Also see graph

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