Question

Fill in the blank __ pi/3 sinpi/6=1/2(sinpi/2-sinpi/6)

Answer 1

_ π/3 · sin π/6 = 1/2 · ( sin π/2  - sin π/6 )
Lets start from the right side of the equation:
1/2 · ( sin π/2 - sin π/6 ) = 1/2 · ( 1 - 1/2 ) = 1/2 · 1/2 = 1/4
So the left side must be equal:
_ π/3 · sin π/6 = 1/4
_ π/3 · 1/2 = 1/4
_ π/3 = 1/4 : 1/2 = 1/4 · 2/1 = 1/2
cos π/3 = 1/2
Answer:
cos π/3 · sin π/6 = 1/2 ( sin π/2 - sin π/6 ) 

Answer 2

Answer:

_ π/3 · sin π/6 = 1/2 · ( sin π/2  - sin π/6 )

Lets start from the right side of the equation:

1/2 · ( sin π/2 - sin π/6 ) = 1/2 · ( 1 - 1/2 ) = 1/2 · 1/2 = 1/4

So the left side must be equal:

_ π/3 · sin π/6 = 1/4

_ π/3 · 1/2 = 1/4

_ π/3 = 1/4 : 1/2 = 1/4 · 2/1 = 1/2

cos π/3 = 1/2

Answer:

cos π/3 · sin π/6 = 1/2 ( sin π/2 - sin π/6 )