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pogonyaev
3 years ago
11

Then choose the point P below that has the following property: If point P is added to the given set of points, then point P woul

d be in a closest pair of points, and all the currently existing closest pairs would also still remain closest pairs.
a) (0,5)
b) (16,-1)
c) (14,4)
d) (22,11)
Mathematics
1 answer:
likoan [24]3 years ago
5 0

Answer:

when the point p is added to set of points. the closest pairs would be (a) (0,5)

Step-by-step explanation:

Because at 0 the value of x is at its minimal or its simply at the origin.

hence we conclude that the closest point when p is added to the given set of points is (0,5)

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From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
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Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

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<u>Formulas</u>

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\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

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\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

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\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

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