Consider a reaction in which two reactants make one product (for example, consider the unbalanced reaction ). You know the follo
1 answer:
Answer: The maximum amount of C that can be produced is 2.0 mol.
Explanation:
The balanced equation will be as follows.
As we are given that,
moles of C = moles of A = moles of B
When we react 2.0 mol A with 3.0 mol B then the limiting reagent is A as specie A has less number of moles. Therefore, the maximum amount of C which can be produced is as follows.
= 2.0 mol
Therefore, we can conclude that the maximum amount of C that can be produced is 2.0 mol.
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To get the number of gold atoms, you have to divide the mass of the gold by the mass of the gold atom. It follows this simple equation 
.
Let x be the number of gold atoms. Plug in the values to a calculator.
x =
Both have the same units so the unit gram(g) can be cancelled.
x then would be equal to 1.53x10^22. So there are 1.53x10^22 atoms of gold in 5 g of gold
Let x be the number of gold atoms. Plug in the values to a calculator.
x =
Both have the same units so the unit gram(g) can be cancelled.
x then would be equal to 1.53x10^22. So there are 1.53x10^22 atoms of gold in 5 g of gold
The question is incomplete, here is the complete question:
Silicon reacts with carbon dioxide to form silicon carbide and silicon dioxide. Write the balanced chemical equation.
<u>Answer:</u> The balanced chemical equation is written below.
<u>Explanation:</u>
Every balanced chemical equation follows law of conservation of mass.
A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.
The balanced chemical equation for the reaction of silicon and carbon dioxide follows:
By Stoichiometry of the reaction:
2 moles of silicon reacts with 1 mole of carbon dioxide gas to produce 1 mole of silicon carbide and 1 mole of silicon dioxide
Hence, the balanced chemical equation is written above.