y’all i have this same question someone please help
Answer:
The answer is A.
Explanation:
C6H12O6 + 6O2 -> 6CO2 + 6H20
C6H12O6 + 6O2 -> 6CO2 + 6H20At the reactant side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.
atoms, 12 hydrogen atoms and 18 oxygen atoms.At product side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.
(In a balanced equation, the no. of atoms on the reactant side must be <em><u>e</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>l</u></em><em> </em>to the no. of atoms on the product side)
Answer : The value of reaction quotient, Q is 0.0625.
Solution : Given,
Concentration of 
= 2.00 M
Concentration of 
= 2.00 M
Concentration of 
= 1.00 M
Reaction quotient : It is defined as a concentration of a chemical species involved in the chemical reaction.
The balanced equilibrium reaction is,
The expression of reaction quotient for this reaction is,
![Q=\frac{[Product]^p}{[Reactant]^r}\\Q=\frac{[NH_3]^2}{[N_2]^1[H_2]^3}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BProduct%5D%5Ep%7D%7B%5BReactant%5D%5Er%7D%5C%5CQ%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5E1%5BH_2%5D%5E3%7D)
Now put all the given values in this expression, we get
Therefore, the value of reaction quotient, Q is 0.0625.
Answer:
The formula of the compound is:
N2H2
Explanation:
Data obtained from the question:
Nitrogen (N) = 93.28%
Hydrogen (H) = 6.72%
Next, we shall determine the empirical formula for the unknown compound. This is illustrated below:
N = 93.28%
H = 6.72%
Divide by their molar mass
N = 93.28 /14 = 6.663
H = 6.72 /1 = 6.7
Divide by the smallest
N = 6.663 / 6.663 = 1
H = 6.72 /6.663 = 1
Therefore, the empirical formula is NH.
Now, we can obtain the formula of the compound as follow:
The formula of a compound is simply a multiple of the empirical formula.
[NH]n = 30.04
[14 + 1]n = 30.04
15n = 30.04
Divide both side by 15
n = 30.04/15
n = 2
Therefore, the formula of the compound is:
[NH]n => [NH]2 => N2H2
