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ohaa [14]
2 years ago
12

What Most Often Causes The Availability Of Water To Change?

Chemistry
1 answer:
Margaret [11]2 years ago
8 0

Answer:the answer is C

Explanation:

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A rock is found to have a mass of 200 g and a volume of 100 ml. what is the rock's density?
GaryK [48]
Mass over volume
200 over100
2
4 0
3 years ago
the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel
shtirl [24]

<u>Answer:</u> The entropy change of the process is 2.0\times 10^2J/K

<u>Explanation:</u>

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{f}}{T}

where,  

\Delta S = Entropy change

n = moles of acetone = 6.3 moles

\Delta H_{f} = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol    (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = -94.7^oC=[273-94.7]=178.3K

Putting values in above equation, we get:

\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K

Hence, the entropy change of the process is 2.0\times 10^2J/K

4 0
3 years ago
How many Na and Cl molucules are in this atom? Please help
kati45 [8]
5 Na molecules and 5 Cl molecules
5 0
2 years ago
Read 2 more answers
How many molecules are contained in 0.800 mol o2?
Ksenya-84 [330]
Multiply .800 moles of O2 by Avagadro's number divided by 1 mole. This will get rid of the moles on the bottom and leave you with molecules. So technically .800 times 6.02x10^23.
6 0
3 years ago
Identify the products in the equation below (the “I” is Iodine—to differentiate capital “I” from lowercase “l”)
Inessa [10]

Answer : The products are Silver sulfide, (Ag_2S) and Sodium iodide, (NaI).

Explanation :

The given balanced chemical reaction is,

2AgI+Na_2S\rightarrow Ag_2S+2NaI

From the given balanced reaction, we conclude that the 2 moles of silver iodide react with the 1 mole of sodium sulfide to give product as 1 mole of silver sulfide and 2 moles of sodium iodide.

In a chemical reaction, reactants are represent on the left side of the right-arrow and products are represent on the right side of the right-arrow.

Therefore, in a chemical reaction the products are Silver sulfide and Sodium iodide.


5 0
3 years ago
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