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Setler [38]
3 years ago
14

Which of the following is the correct expression for the rate of the following reaction

Chemistry
1 answer:
iris [78.8K]3 years ago
7 0
B. 
<span>[H2O] / [H2S]  is the correct answer</span>
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If you have 1.005 x 1024 molecules of Ca(OH)2 how many atoms do you have? Moles? Grams?
ira [324]

Answer:

  • 5.025x10²⁴ atoms
  • 1.6686 moles
  • 123.63 g

Explanation:

In one Ca(OH)₂ molecule, there are 5 atoms (1 Ca, 2 O and 2 H). This means that in 1.005x10²⁴ Ca(OH)₂ molecules, there are (5 * 1.005x10²⁴) 5.025x10²⁴ atoms.

To <u>convert molecules into moles</u>, we use <em>Avogadro's number</em>:

  • 1.005x10²⁴ molecules * \frac{1mol}{6.023*10^{23}molecules} = 1.6686 moles

Finally, we <u>convert moles into grams</u> using the <em>molar mass of Ca(OH)₂</em>:

  • 1.6686 moles * 74.093 g/mol = 123.63 g
4 0
3 years ago
Le Châtelier's principle tells us that chemical _____ will adjust in an attempt to remove a stressor.
lawyer [7]
Le Châtelier's principle tells us that chemical <span>c. equilibrium </span>will adjust in an attempt to remove a stressor.
8 0
3 years ago
What is the mass of 8.12 × 10^23 molecules of CO2 gas? (Atomic mass of carbon = 12.011 u; oxygen = 15.999 u.)
amid [387]

Answer:

m=59.3gCO_2

Explanation:

Hello,

In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:

M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol

It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:

mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol

Finally, the mass by using the molar mass:

m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2

Best regards.

4 0
3 years ago
PLS HELP ASAP <br><br> How does the mass of an object affect its force?
seraphim [82]

Answer:

If mass increases, force increases.

Explanation:

hope this helps, pls mark brainliest :D

5 0
3 years ago
Products: 1-methylcyclohexene, 3-methylcyclohexene, methylenecyclohexane
Lostsunrise [7]

Answer:

See explanation

Explanation:

The reaction that we are considering here is quite a knotty reaction. It is difficult to decide if the mechanism is actually E1 or E2 since both are equally probable based on the mass of scientific evidence regarding this reaction. However, we can easily assume that the methylenecyclohexane was formed by an E1 mechanism.

Looking at the products, one could convincingly assert that the reaction leading to the formation of the two main products proceeds via an E1 mechanism with the formation of a carbocation intermediate as has been shown in mechanism attached to this answer. Possible rearrangement of the carbocation yields the 3-methylcyclohexene product.

8 0
3 years ago
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