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Katyanochek1 [597]
3 years ago
11

SO4 + KBr → SnBr2 + K2SO4 i need this balanced

Chemistry
1 answer:
Mars2501 [29]3 years ago
3 0
<span>the balance is SnSO4 + 2 KBr = SnBr2 + K2SO<span>4</span></span>
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A balloon contains 11.1 g of nitrogen monoxide gas (NO). how many molecules are in the balloon?
grandymaker [24]

The number of molecules that are in balloon are = 2.227 x10^23 molecules

<h3> calculation</h3>

calculate the number of moles of NO

moles = mass/molar mass

molar mass  of NO = 14+ 16 = 30 g/mol

moles is therefore=  11.1 g/30g/mol= 0.37 moles

by use of Avogadro's constant that is

                                     1 mole= 6.02 x10^23  molecules

                                          0.37 =? molecules

=(6.02 x10^23 x  0.37 moles)/ 1mole=2.227 x10^23 molecules

4 0
3 years ago
What are crystalline solids
OverLord2011 [107]

Answer:

A solid material whose constituents (such as atoms, molecules, or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.

Explanation:

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3 years ago
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Answer:

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Read 2 more answers
1)If I mixed salt in water I would expect the salt to:
zaharov [31]

Answer:

1)If I mixed salt in water I would expect the salt to: dissolve.

2) If I mixed starch in water I would expect the starch to: remain undissolved.

Explanation:

Hello,

In this case, since salt, which is commonly known as sodium chloride (NaCl) is an ionic compound, it is very likely to get dissolved in water, therefore, we would expect the salt to dissolve and form a liquid solution.

Moreover, since start is mainly composed by C-C, C-O and C-H bonds which are nonpolar, it we can say it is usually insoluble in water, therefore we will expect starch to remain undissolved but undergoing a process called gelatinization in which a suspension in formed until a slightly solid consistency.

Best regards.

4 0
3 years ago
How much energy (in Joules) would it take to warm 3.11 grams of gold by 7.7 oC
Reptile [31]

Answer:

It would take 3.11 J to warm 3.11 grams of gold

Explanation:

Step 1: Data given

Mass of gold = 3.11 grams

Temperature rise = 7.7 °C

Specific heat capacity of gold = 0.130 J/g°C

Step 2: Calculate the amount of energy

Q = m*c*ΔT

⇒ Q = the energy required (in Joules) = TO BE DETERMINED

⇒ m = the mass of gold = 3.11 grams

⇒ c = the specific heat of gold = 0.130 J/g°C

⇒ ΔT = The temperature rise = 7.7 °C

Q = 3.11 g * 0.130 J/g°C * 7.7 °C

Q = 3.11 J

It would take 3.11 J to warm 3.11 grams of gold

4 0
3 years ago
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