Take your x values in each coordinate and subtract 2, and take your y values and subtract 1.
Q (0-2), (-1-1)
= (-2,-2)
D (-2-2), (2-1)
= (-4, 1)
V (2-2), (4-1)
= (0,3)
J (3-2), (0-1)
= (1,-1)
You can also draw it on a graph and then translate all coordinates 2 units left and 1 down to see the end results.
469 is the perece to equivalent to 75 becuase it’s bigger
Answer:
32 divided by 4 = 8,
8^2 + 8^2 = 128
128: 11^2 = 121 close enough, 11 is your answer
We are finding hypotenuse but first we find the length of all sides of the two squares to find the two sides of the triangle then we find hypotenuse.
Horizontal cross sections are the same shape: they are all squares if the pyramid is square or rectangles if the pyramid is a rectangle pyramid.
Vertical cross sections are different shape: At the pyramid top they are triangles, at other places they have four sides.
Horizontal cross sections are different size: the more we go to the top of the pyramind, the smaller they get.
Vertical cross sections are different size: the closer we get to the edges, the smaller they become.
For the answer to the question above asking to f<span>ind the coordinates of Z without using any new variables.
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Vector WZ equals vector VP, which is (p, -q)
So Z is (-p - r + p, q - q) which is (-r, 0)
I hope my answer helped you.