Answer:
no of cycle required is 1885.3
Explanation:
given data
thermal energy Q1 = 75 J
thermal energy Q2 = 115 J
load = 3454 kg
distance = 27 m
steady rate = 52.5 mm/s
to find out
How many cycles of the engine are need
solution
we find here first work done that is express as
work done W = Q2 - Q1 ..................1
put here all these value
W = 115 - 75
work done is 40 J
so energy required is
Energy required E = m×g×h ..................2
put here value
E = 285 × 9.8 × 27
energy required = 75411 J
so here no of cycle is
no of cycle = energy required / work done
put here value
no of cycle required = 75411 / 40
so no of cycle required is 1885.3
