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Delicious77 [7]

2 years ago

15

How do you test hydrogen gas

2 answers:

Luda [366]2 years ago

7 0

Answer:

You can test for hydrogen gas by putting a burning splinter near the gas. The splinter will gives out a 'pop' sound (mini explosion) if it is hydrogen gas

Vanyuwa [196]2 years ago

3 0

Explanation:

A splint is lit and held near the opening of the tube, then the stopper is removed to expose the splint to the gas. If the gas is flammable, the mixture ignites. This test is most commonly used to identify hydrogen, which extinguishes with a distinctive 'squeaky pop' sound.

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Answer question 83 and 84

Ne4ueva [31]

83. Gravity is activity as a force on the cart.

84. The box has gathered kinetic energy and momentum and will continue going forward.

6 0

3 years ago

SI is considered a consistent system because it what

NemiM [27]

Answer:

because it is a worldwide system....

Explanation:

5 0

2 years ago

The Sun is about 150 million km from earth. how long does it take light from the sun to reach earth? (Speed of light is 3x10^8m/

madam [21]

Time =      (distance) / (speed)

Time = (150 x 10⁹ m) / (3 x 10⁸ m/s) =

   50 x 10¹ sec =

       <em>500 sec</em> = 8 min 20 sec

3 0

3 years ago

A lady holds a large concave mirror of focal length 1.8m from her face.State two characteristics of her image in the mirror.

Vlada [557]

Answer:

reflection and refraction?

Explanation:

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Kit

6 0

3 years ago

Given two vectors A=4i^+3j^ and vector<br> B=5i^-2j^.find the magnitude of each vector

Flura [38]

Answer:

<em>Magnitude of A=5</em>

<em>Magnitude of B=5.39</em>

Explanation:

<u>The magnitude of Vectors in Rectangular Form</u>

Given a vector v in its rectangular form:

$\mathbf{v}=x\hat i+y\hat j$

The magnitude of v is:

$\mid\mid\mathbf{v}\mid \mid=\sqrt{x^2+y^2}$

We are given the vectors

$\mathbf{A}=4\hat i+3\hat j$

$\mathbf{B}=5\hat i-2\hat j$

Their magnitudes are:

$\mid\mid\mathbf{A}\mid \mid=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}$

$\mid\mid\mathbf{A}\mid \mid=5$

$\mid\mid\mathbf{B}\mid \mid=\sqrt{5^2+(-2)^2}=\sqrt{25+4}=\sqrt{29}$

$\mid\mid\mathbf{B}\mid \mid=\sqrt{29}=5.39$

4 0

2 years ago