The amount of charge on the plates increases during this process.
Explanation:
The relationship between charge and potential difference through a capacitor is

where
C is the capacitance
Q is the charge stored
is the potential difference
The capacitance of a parallel-plate capacitor is given by

where
is the vacuum permittivity
A is the area of the plates
d is the distance between the plates
Combining the two equations, we get:

In this problem:
- The potential difference between the plates,
, is kept constant
- The area of the plates, A, remains constant
- The distance between the plates, d, is decreased
Since Q is inversely proportional to d, this means that as the plates are pushed together, the amount of charge on the plates increases during the process.
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