The Kevlar jacket is only similar to the spiderweb in the arrangement of atoms in molecules of both substances.
<h3>Similarity between spiderweb and a Kevlar jacket</h3>
A spider web refers to the tiny web-like structures that is seen around places where spiders breed. On the other hand the Kevlar jacket is known for its high tensile strength.
The Kevlar jacket is only similar to the spiderweb in the arrangement of atoms in molecules of both substances.
Learn more about molecule: brainly.com/question/19922822
Answer:
I think that the answer is B or a
Explanation:
Answer:
The specific heat capacity is 0.67 ![\frac{J}{g*C}](https://tex.z-dn.net/?f=%5Cfrac%7BJ%7D%7Bg%2AC%7D)
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
The amount of heat that a body receives or transmits is determined by the following expression:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
This expression indicates that between heat and temperature there is a direct proportional relationship.
In this case:
- Q= 100 J
- c= ?
- m= 5 g
- ΔT= Tfinal - Tinitial= 40 °C - 10 °C= 30 °C
Replacing:
100 J= c*5 g* 30°C
Solving:
![c=\frac{100 J}{5 g* 30C}](https://tex.z-dn.net/?f=c%3D%5Cfrac%7B100%20J%7D%7B5%20g%2A%2030C%7D)
c= 0.67 ![\frac{J}{g*C}](https://tex.z-dn.net/?f=%5Cfrac%7BJ%7D%7Bg%2AC%7D)
<u><em>The specific heat capacity is 0.67 </em></u>
<u><em></em></u>
Answer:
![\text{(a) }8.187 \times 10^{-14}\text{ J}; \text{(b) 49 300 kJ/mol; (c) } 5.110 \times 10^{5}\text{ eV}](https://tex.z-dn.net/?f=%5Ctext%7B%28a%29%20%7D8.187%20%5Ctimes%2010%5E%7B-14%7D%5Ctext%7B%20J%7D%3B%20%5Ctext%7B%28b%29%2049%20300%20kJ%2Fmol%3B%20%28c%29%20%7D%205.110%20%5Ctimes%2010%5E%7B5%7D%5Ctext%7B%20eV%7D)
Explanation:
This question involves the conversion of mass into energy: E = mc².
e + p ⟶ γ + γ
Each particle has the same mass so, in terms of mass, we can write
2e ⟶ 2γ or
e ⟶ γ
Thus, we can just convert the mass of an electron to its energy equivalent.
(a) Energy in joules
![E= 9.109 \times 10^{-28}\text{ kg} \times \left (2.998 \times 10^{8}\text{ m$\cdot$s}^{-1}\right )^{2} = \mathbf{8.187 \times 10^{-14}}\textbf{ J}](https://tex.z-dn.net/?f=E%3D%209.109%20%5Ctimes%2010%5E%7B-28%7D%5Ctext%7B%20kg%7D%20%5Ctimes%20%5Cleft%20%282.998%20%5Ctimes%2010%5E%7B8%7D%5Ctext%7B%20m%24%5Ccdot%24s%7D%5E%7B-1%7D%5Cright%20%29%5E%7B2%7D%20%3D%20%5Cmathbf%7B8.187%20%5Ctimes%2010%5E%7B-14%7D%7D%5Ctextbf%7B%20J%7D)
(b) Energy in kilojoules per mole
![E =8.187 \times 10^{-14}\text{ J } \times \dfrac{\text{ 1 k}}{\text{1000 J}} \,\times \,\dfrac{6.022 \times 10^{23}}{\text{1 mol}} = 4.930 \times 10^{7}\text{ J/mol}= \textbf{49 300 kJ/mol}](https://tex.z-dn.net/?f=E%20%3D8.187%20%5Ctimes%2010%5E%7B-14%7D%5Ctext%7B%20J%20%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B%201%20k%7D%7D%7B%5Ctext%7B1000%20J%7D%7D%20%5C%2C%5Ctimes%20%5C%2C%5Cdfrac%7B6.022%20%5Ctimes%2010%5E%7B23%7D%7D%7B%5Ctext%7B1%20mol%7D%7D%20%3D%204.930%20%5Ctimes%2010%5E%7B7%7D%5Ctext%7B%20J%2Fmol%7D%3D%20%5Ctextbf%7B49%20300%20kJ%2Fmol%7D)
(c) Energy in electron volts
![E = 8.187 \times 10^{-14}\text{ J}\times \dfrac{6.242 \times 10^{18}\text{ eV}}{\text{1 J}} = \mathbf{5.110 \times 10^{5}}\textbf{ eV}](https://tex.z-dn.net/?f=E%20%3D%208.187%20%5Ctimes%2010%5E%7B-14%7D%5Ctext%7B%20J%7D%5Ctimes%20%5Cdfrac%7B6.242%20%5Ctimes%2010%5E%7B18%7D%5Ctext%7B%20eV%7D%7D%7B%5Ctext%7B1%20J%7D%7D%20%3D%20%5Cmathbf%7B5.110%20%5Ctimes%2010%5E%7B5%7D%7D%5Ctextbf%7B%20eV%7D)