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3 years ago

DNA What organism is often used to study mutations

Chemistry

1 answer:

bezimeni [28]3 years ago

6 0

Answer:

Hartwell's yeast

Explanation: A model organism for studying somatic mutations and cancer."

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A gas mixture contains 3.0 mol of hydrogen (H2) and 7.3 mol of nitrogen (N2). The total pressure of the mixture is 304 kPa. What

Inga [223]

Answer:

Mole fraction H₂ = 0.29

Partial pressure of H₂ → 88.5 kPa

Explanation:

You need to know this relation to solve this:

Moles of a gas / Total moles = Partial pressure of the gas / Total pressure

Total moles = 3 mol + 7.3 mol → 10.3 moles

Mole fraction H₂ → 3 moles / 10.3 moles = 0.29

Mole fraction = Partial pressure of the gas / Total pressure

0.29 . 304 kPa = Partial pressure of H₂ → 88.5 kPa

5 0

4 years ago

A sample of Manganese (II) chloride has a mass of 19.8 grams before heating, and 12.6 grams after heating until all the water is

IRINA_888 [86]

Answer:

no. of water molecules associated to each molecule of $MnCl_2$ = 4

Explanation:

Mass of $MnCl_2$ before heating = 19.8 g

Mass of $MnCl_2$ after heating = 12.6 g

Difference in mass of $MnCl_2$ before and after heating

= 19.8 - 12.6 = 7.2 g

Difference in mass corresponds to mass of water driven out.

Molar mass of water = 18 g/mol

No. of moles of water = $\frac{7.2}{18} = 0.4\ mol$

Mass of $MnCl_2$ obtained after heating is mass of anhydrous $MnCl_2$ .

Mass of anhydrous $MnCl_2$ = 12.6 g

Molar mass of $MnCl_2$ = 125.9 g/mol

No. of mol of anhydrous $MnCl_2$ = $\frac{125.9}{125.9} = 0.1\ mol$

so,

0.1 mol of $MnCl_2$ have 0.4 mol of water

1 mol of $MnCl_2$ will have = $\frac{0.4}{0.1} =4\ mol$

Hence, no. of water molecules associated to each molecule of $MnCl_2$ = 4

5 0

3 years ago

Equation below is used to determine the heat flux for convection

OLEGan [10]

Q=hc A (Ts-Ta)
q = heat transfered per unit time
A= heat transfer area of the surface
hc= convective heat transfer coefficient of the process
Ts= temperature of the surface
Ta= temperature of the air

7 0

3 years ago

How many grams of carbon dioxide are produced from the combustion of 250.G of ethane, C3H8 in the reaction C3H8 +5O2 - 3CO2 +4H2

ludmilkaskok [199]

Answer:

750 g of CO₂

Explanation:

The balanced equation for the reaction is given below:

C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O

Next, we shall determine the mass of C₃H₈ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C₃H₈ = (12×3) + (8×1)

= 36 + 8 = 44 g/mol

Mass of C₃H₈ from the balanced equation = 1 × 44 = 44 g

Molar mass of CO₂ = 12 + (16×2)

= 12 + 32 = 44 g/mol

Mass of CO₂ = 3 × 44 = 132 g

SUMMARY:

From the balanced equation above,

44 g of C₃H₈ reacted to produce 132 g of CO₂.

Finally, we shall determine the mass of CO₂ produced by the reaction of 250 g of C₃H₈. This can be obtained as follow:

From the balanced equation above,

44 g of C₃H₈ reacted to produce 132 g of CO₂.

Therefore, 250 g of C₃H₈ will react to produce = (250 × 132)/44 = 750 g of CO₂.

Thus, 750 g of CO₂ were obtained from the reaction.

8 0

3 years ago

What must be true for a substance to be able to dissolve in water?

JulsSmile [24]

B. i think not 100% sure

6 0

3 years ago