B) Cu(OH) 2 Is the resulting answer when H20 is decomposed.
Answer:
eukaryotic because it has a nucleus
Explanation:
Answer:
Energy equivalent to mass defect is termed as binding energy. A nucleus is like an inflexible spherical ball moulded by getting together a huge amount of miniature spherical balls in the nucleons form. Something is required to bound the nucleons collected. It is that something which assists as the glue. Every nucleon has to donate some of its mass, to deliver the energy resulting in a mass defect.
Binding Energy is also defined as the energy required to break down a nucleus into its component nucleons.
Binding Energy is expressed in terms of kJ/mole of nuclei or MeV’s/nucleon.
Binding Energy Formula
Binding Energy = mass defect x c2
where c= speed of light in vacuum
c = 2.9979 x 108 m/s.
Valence electrons of elements except the transition elements – the main group elements. While the period number indicates the number of shells, the group number indicates the number of valence electrons in the outermost shell. Specifically, the number in the ones' place. It can never be replaced rarely anyways.
Answer:
Mass of PbS = 9.26 g
Explanation:
Data Given :
mass of H₂S = 5.00 g
mass of PbS = ?
Reaction Given:
Pb(CH₃COO)₂ + H₂S ----→ PbS + CH₃COOH
Solution:
Balance the equation:
Pb(CH₃COO)₂ + H₂S ----→ PbS + 2CH₃COOH
Now Look for the number of moles of H₂S and PbS meta
Pb(CH₃COO)₂ + H₂S ----→ PbS + 2CH₃COOH
1 mol 1 mol
So,
1 mole of H₂S combine with excess (unlimited) supply of Pb(CH₃COO)₂ and produce 1 moles of PbS
Now Convert moles to mass for which we have to molar masses of H₂S and PbS
Molar mass of H₂S = 2 + 32 = 43 g/mol
Molar mass of PbS = 31 + 32 = 63 g/mol
Pb(CH₃COO)₂ + H₂S -------→ PbS + 2CH₃COOH
1 mol (34 g/mol) 1 mol (63 g/mol)
34 g 63 g
So,
34 g of H₂S produces 63 grams of PbS.
Now
What mass of silver is produced from 5 g of H₂S
Apply unity formula
34 g of H₂S ≅ 63 g of PbS
5 g of H₂S ≅ X g of PbS
By doing cross multiplication
Mass of PbS = 63 g x 5 g / 34 g
Mass of PbS = 9.26 g
