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2 years ago

DNA What organism is often used to study mutations

Chemistry

1 answer:

bezimeni [28]2 years ago

6 0

Answer:

Hartwell's yeast

Explanation: A model organism for studying somatic mutations and cancer."

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Acid deposition results from burning fossil fuels that release ___________ that react in the atmosphere to form acids that fall

AysviL [449]

Sulfur dioxide. this is the cause

4 0

2 years ago

A leader from Louisiana is claiming that it is necessary to include the effects of tornadoes in his city’s emergency plan for na

kaheart [24]

Answer:

i dont know either im sorry

Explanation:

6 0

2 years ago

How many atoms are in 5 moles of Cadmium?

forsale [732]

<h3>Answer:</h3>

3 × 10²⁴ atoms Cd

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

5 mol Cd (Cadmium)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 5 \ moles \ Cd(\frac{6.022 \cdot 10^{23} \ atoms \ Cd}{1 \ mol \ Cd})$
Multiply: $\displaystyle 3.011 \cdot 10^{24} \ atoms \ Cd$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

3.011 × 10²⁴ atoms Cd ≈ 3 × 10²⁴ atoms Cd

5 0

2 years ago

Zn+2HCl=ZnCl2+H2 how many moles of ZnCl2 will be produced from 61.0 g of ZnCl2, assuming HCl is available in excess?

docker41 [41]

Answer:
127.15 g of ZnCl₂

Solution:
The balance chemical equation is as follow,

<span> Zn + 2 HCl </span>→ ZnCl₂ + H₂

According to equation,

65.38 g (1 mole) of Zn produced = 136.28 g (1 mole) of ZnCl₂
So,
61.0 g of Zn will produce = X g of ZnCl₂

Solving for X,
X = (61.0 g × 136.28 g) ÷ 65.38 g

X = 127.15 g of ZnCl₂

5 0

3 years ago

Read 2 more answers

A gas originally occupying 10.1 L at 0.925 atm and 25 C is changed to 12.2 L at 625 torr. What is the new temperature?

IrinaVladis [17]

We can use the combined gas law equation to find the new temperature
$\frac{P1V1}{T1} = \frac{P2V2}{T2}$
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
P - pressure
P1 - 0.925 atm x 101 325 Pa/atm = 93 726 Pa
P2 - 625 torr x 133 Pa/torr = 83 125 Pa
V - volume
V1 - 10.1 L
V2 - 12.2 L
T - temperature in kelvin
T1 - 25 °C + 273 = 298 K
substituting these values in the equation
$\frac{93726Pa * 10.1L }{298K} = \frac{83125 Pa*12.2L}{T2}$
T = 319 K
temperature in celsius - 319 K - 273 = 46 °C

3 0

3 years ago