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SIZIF [17.4K]
3 years ago
6

Steven had a sample of ethanol and wanted to see if it would boil at the temperature found in his textbook. His experiment yield

ed a temperature of 143.6oF but the literature value was 173.1oF. What is the percent error in this experiment?
Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
4 0

Answer:

17.04%

Explanation:

Actual Value = 173.1

Measured Value = 143.6

Percent error is obtained using the equation;

Percent error = (Measured - Actual) / Actual ]* 100

Percent error = [ (143.6 - 173.1) / 173.1 ] * 100

The absolute value of (Measured - Actual) is taken,

Percent Error = [29.5 / 173.1 ] * 100

Percent Error = 0.1704 * 100 = 17.04%

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Answer:

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Explanation:

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V = πr²h

radius r = Diameter / 2 = 27 cm / 2 = 13.5 cm

height h = 32.4 cm

so we substitute

V = π × ( 13.5 cm )² × 32.4 cm

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molar mass of carbon monoxide gas is 28.010 g/mol

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PV = nRT

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T = PV / nR

we know that gas constant R = 0.0820574 L•atm•mol⁻¹ K⁻¹

so we substitute

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