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maksim [4K]
2 years ago
13

Tinh can row at a rate of 6 mph in still water. It takes her 2 hours to row upstream from a dock to a park. She then rows back t

o the dock, and it only takes 40 minutes. What is the speed of the river current? 3 mph 12 mph 18 mph 48 mph
Mathematics
2 answers:
scZoUnD [109]2 years ago
7 0

Answer:

Option A is correct, i.e. 3 mph.

Step-by-step explanation:

Tinh can row at a rate of 6 mph in still water.

Suppose the speed of the river current is X mph.

Then Upstream speed = (6-X) mph.

And Downstream speed = (6+X) mph.

It takes her 2 hours to row upstream from a dock to a park. She then rows back to the dock, and it only takes 40 minutes.

It means Distance upstream = Distance downstream.

Speed upstream x Time upstream = Speed downstream x Time downstream.

(6-x) * 2 = (6+x) * 40/60

12 - 2x = 4 + 2x/3

12 - 4 = 2x/3 + 2x

8 = 2x/3 + 6x/3 = 8x/3

x = 3 mph.

Hence, option A is correct, i.e. 3 mph.

Mariulka [41]2 years ago
7 0

Answer:

Option A (3)

Step-by-step explanation:

Given that Tinh can row at a rate of 6 mph in still water.

Also it takes her 2 hours to row upstream from a dock to a park. She then rows back to the dock, and it only takes 40 minutes.

While upstream she travels against the stream but while downstream she travels along with the stream

Let x  be the speed of boat in still water and y that of stream

Then since distance d is the same, time x speed =D

i.e. (x-y)120 = (x+y)40 after converting hours to minutes

80x=160y

x=2y

x=6 (given)

So y = 6/2=3 mph




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\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }

\large\underline{  \boxed{ \sf{✰\:Important\: point's }}}

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{ \rule{70mm}{2.9pt}}

\underline{  \boxed{ \sf{✵\: let's\: solve\:✵}}}

\sf ➛\angle \: 120 \degree + \angle \:t  = 180\degree \\   \sf ➛\angle  \:t = 180 \degree -   \angle \:120 \degree \\   \sf ➛\angle \: t =  \:60 \degree

{ \rule{70mm}{2.9pt}}

\boxed{✛\underline{  \boxed{ \sf{ \: \angle \: t = 60 \degree  \: }}}✛}

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