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Vesna [10]
3 years ago
11

What is 5 1/5 times 2 3/4

Mathematics
2 answers:
Hitman42 [59]3 years ago
7 0

Answer:

14  3/10

Step-by-step explanation:

5 1/5 * 2 3/4

Change to improper fractions

5 1/5  = (5*5+1) /5 = 26/5

2 3/4 = (4*2+3)/4 = 11/4

26/5 * 11/4 = 286/20

Divide top and bottom by 2

143/10

10 goes into 143 14 times with 3 left over

14 3/10

yKpoI14uk [10]3 years ago
6 0

Answer: 14.3

Step-by-step explanation:

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PLEASE HELP!! I’LL MAKE YOU BRAINIEST!
Leokris [45]

Answer:

1. Markup: $2.70, Retail: $20.70

2. Markup: $9.45, Retail: $31.95

3. Markup: $25.31, Retail: $59.00

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5. Markup: $48.60, Retail: $97.20

6. Markup: $231.25, Retail: $416.25

Step-by-step explanation:

To get the markup price of an item, multiply it by the markup percentage as a decimal. To get the decimal of a percentage, divide the number by 100. For example, 15% would be 0.15. And then to find how much the item has been marked up by, multiply the current price by the decimal.

$18 * 0.15 = $2.70

So $2.70 is the markup. To find the retail price, you need to add the markup price to the current price given.

$18 + $2.70 = $20.70

So your retail price is $20.70. Repeat these steps for each question to get the answers above.

Hope this helps.

7 0
2 years ago
Approximate the distance between (1,2) and (7, 6) to the nearest tenth.
viva [34]

Check image below for answer!

4 0
1 year ago
Given lines p and q are parallel, find the value of x that makes each diagram true.
Klio2033 [76]

Answer: for a the answer is 140° and for b x=25°

Step-by-step explanation:

for a, when you have 2 parallel lines cut by a transversal,the corresponding angles are congruent. and the angle140 is congruent to the corresponding angle as they are vertical angles are congruent.

for b, angle x is congruent to the angle that is supplementary to 155 therefore 180-155=25°

5 0
3 years ago
Brad bought a piece of industrial real estate for $192,345. The value of the real estate appreciated a constant rate per year. T
Zanzabum

Answer:

D. f(t) = 192,345(1.04)^t

Step-by-step explanation:

<em>I took the test and it was right. </em>

Also that is the original price and when you look at exponential functions, the starting point or original price is always first the then rate of increase. The table just shows how it increased in year 1 and 2.

Hope this helps. :)

4 0
3 years ago
The focus of a parabola is (−5,−1) and the directrix is y=−3. What is an equation of the parabola? (x+5)2=8(y+5)
Anna35 [415]
<span><span>Graph <span>x2<span> = 4</span>y</span><span> and state the vertex, focus, axis of symmetry, and directrix.</span></span><span>This is the same graphing that I've done in the past: </span><span>y = (1/4)x2</span><span>. So I'll do the graph as usual:</span></span><span> </span><span>The vertex is obviously at the origin, but I need to "show" this "algebraically" by rearranging the given equation into the conics form:<span>x2 = 4y</span> Copyright © Elizabeth Stapel 2010-2011 All Rights Reserved<span>
(x – 0)2 = 4(y – 0)</span><span>This rearrangement "shows" that the vertex is at </span><span>(h, k) = (0, 0)</span><span>. The axis of symmetry is the vertical line right through the vertex: </span><span>x = 0</span>. (I can always check my graph, if I'm not sure about this.) The focus is "p" units from the vertex. Since the focus is "inside" the parabola and since this is a "right side up" graph, the focus has to be above the vertex.<span>From the conics form of the equation, shown above, I look at what's multiplied on the unsquaredpart and see that </span><span>4p = 4</span><span>, so </span><span>p = 1</span><span>. Then the focus is one unit above the vertex, at </span>(0, 1)<span>, and the directrix is the horizontal line </span><span>y = –1</span>, one unit below the vertex.<span>vertex: </span>(0, 0)<span>; focus: </span>(0, 1)<span>; axis of symmetry: </span><span>x<span> = 0</span></span><span>; directrix: </span><span>y<span> = –1</span></span></span><span><span><span>Graph </span><span>y2<span> + 10</span>y<span> + </span>x<span> + 25 = 0</span></span>, and state the vertex, focus, axis of symmetry, and directrix.</span><span>Since the </span>y<span> is squared in this equation, rather than the </span>x<span>, then this is a "sideways" parabola. To graph, I'll do my T-chart backwards, picking </span>y<span>-values first and then finding the corresponding </span>x<span>-values for </span><span>x = –y2 – 10y – 25</span>:<span>To convert the equation into conics form and find the exact vertex, etc, I'll need to convert the equation to perfect-square form. In this case, the squared side is already a perfect square, so:</span><span>y2 + 10y + 25 = –x</span> <span>
(y + 5)2 = –1(x – 0)</span><span>This tells me that </span><span>4p = –1</span><span>, so </span><span>p = –1/4</span><span>. Since the parabola opens to the left, then the focus is </span>1/4<span> units to the left of the vertex. I can see from the equation above that the vertex is at </span><span>(h, k) = (0, –5)</span><span>, so then the focus must be at </span>(–1/4, –5)<span>. The parabola is sideways, so the axis of symmetry is, too. The directrix, being perpendicular to the axis of symmetry, is then vertical, and is </span>1/4<span> units to the right of the vertex. Putting this all together, I get:</span><span>vertex: </span>(0, –5)<span>; focus: </span>(–1/4, –5)<span>; axis of symmetry: </span><span>y<span> = –5</span></span><span>; directrix: </span><span>x<span> = 1/4</span></span></span><span><span>Find the vertex and focus of </span><span>y2<span> + 6</span>y<span> + 12</span>x<span> – 15 = 0</span></span></span><span><span>The </span>y<span> part is squared, so this is a sideways parabola. I'll get the </span>y stuff by itself on one side of the equation, and then complete the square to convert this to conics form.<span>y2 + 6y – 15 = –12x</span> <span><span>
y</span>2 + 6y + 9 – 15 = –12x + 9</span> <span>
(y + 3)2 – 15 = –12x + 9</span> <span>
(y + 3)2 = –12x + 9 + 15 = –12x + 24</span> <span>
(y + 3)2 = –12(x – 2)</span> <span>
(y – (–3))2 = 4(–3)(x – 2)</span></span><span><span>Then the vertex is at </span><span>(h, k) = (2, –3)</span><span> and the value of </span>p<span> is </span>–3<span>. Since </span>y<span> is squared and </span>p<span> is negative, then this is a sideways parabola that opens to the left. This puts the focus </span>3 units to the left of the vertex.<span>vertex: </span>(2, –3)<span>; focus: </span><span>(–1, –3)</span><span>
</span></span>
8 0
3 years ago
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