We need to use the following formula
Δ
n= 4 moles
F= constant= 96500C/mol
let's plug in the values.
ΔG= -(4)(96500)(0.24)=
-92640 J or -92.6 kJ
Answer:
The answer is
<h3>3.75 × 10²⁴ atoms of Al</h3>
Explanation:
To find the number of atoms of Al given it's number of moles we use the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
n = 6.23 mol
We have
N = 6.23 × 6.02 × 10²³
We have the final answer as
<h3>3.75 × 10²⁴ atoms of Al</h3>
Hope this helps you