Answer:
what situation?
Step-by-step explanation:
Answer:
(√2)x/2 or (√2/2)x
Step-by-step explanation:
Let's draw two squares, one with diagonal length x and the other with diagonal length √2. In the second case, the side length is 1, which you can confirm by recalling that 1^2 + 1^2 = 2*1^2 and √2*1^2 = √2.
These two squares are similar, even if they're of different sizes.
Writing an equation of ratios, we get:
side length 1
---------------------- = -------------
x √2
Then (side length)*√2 = x (after cross-multiplication)
and so (side length) = x/√2 or (√2)x/2 or (√2/2)x
Answer: 2.14 %
Step-by-step explanation:
Given : pH measurements of a chemical solutions have
Mean : ![\mu=6.8](https://tex.z-dn.net/?f=%5Cmu%3D6.8)
Standard deviation : ![\sigma=0.02](https://tex.z-dn.net/?f=%5Csigma%3D0.02)
Let X be the pH reading of a randomly selected customer chemical solution.
We assume pH measurements of this solution have a nearly symmetric/bell-curve distribution (i.e. normal distribution).
The z-score for the normal distribution is given by :-
![z=\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
For x = 6.74
![z=\dfrac{6.74-6.8}{0.02}=-3](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B6.74-6.8%7D%7B0.02%7D%3D-3)
For x = 6.76
![z=\dfrac{6.76-6.8}{0.02}=-2](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B6.76-6.8%7D%7B0.02%7D%3D-2)
The p-value =![P(6.74](https://tex.z-dn.net/?f=P%286.74%3Cx%3C6%2C76%29%3DP%28-3%3Cz%3C-2%29)
![P(z](https://tex.z-dn.net/?f=P%28z%3C-2%29-P%28z%3C-3%29%3D0.0227501-%200.0013499%3D0.0214002%5Capprox0.0214)
In percent, ![0.0214\times=2.14\%](https://tex.z-dn.net/?f=0.0214%5Ctimes%3D2.14%5C%25)
Hence, the percent of pH measurements reading below 6.74 OR above 6.76 = 2.14%
YXZ, and YZW I think that’s what the question is asking
Answer:
Step-by-step explanation:
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