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Nataly [62]
4 years ago
5

Can someone pls tell me the right answer pls and thank you

Mathematics
2 answers:
DanielleElmas [232]4 years ago
7 0
The checked are the answers

nadezda [96]4 years ago
6 0

wwe 2k17. hop on. it will help out a lot with stress and tension if you know what i mean

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dsp73
8.25% (decimal) and 33/400 (fraction)
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4 years ago
The surface area of a cylinder is increasing at a rate of 9 pi square meters per hour. The height of the cylinder is fixed at 3
Alekssandra [29.7K]

Answer:

9\pi \text{ cubic meters per hour}

Step-by-step explanation:

Since, the surface area of a cylinder,

A= 2\pi r^2 + 2\pi rh  ................(1)

Where,

r = radius,

h = height,

If A= 36\pi\text{ square meters}, h = 3\text{ meters}

36\pi = 2\pi r^2 + 2\pi r(3)

18 = r^2 + 3r

\implies r^2 + 3r - 18=0

r^2 + 6r - 3r - 18 = 0     ( by middle term splitting )

r(r+6)-3(r+6)=0

(r-3)(r+6)=0

By zero product property,

r = 3 or r = - 6 ( not possible )

Thus, radius, r = 3 meters,

Now, differentiating equation (1) with respect to t ( time ),

\frac{dA}{dt}= 4\pi r\frac{dr}{dt} +2\pi(r\frac{dh}{dt} + h\frac{dr}{dt})

∵ h = constant, ⇒ dh/dt = 0,

\frac{dA}{dt} = 4\pi r \frac{dr}{dt} +2\pi h \frac{dr}{dt}

We have, \frac{dA}{dt}=9\pi\text{ square meters per hour}, r = h = 3\text{ meters}

9\pi = 4\pi (3) \frac{dr}{dt}+2\pi (3)\frac{dr}{dt}

9\pi = (12\pi + 6\pi )\frac{dr}{dt}

9\pi = 18\pi \frac{dr}{dt}

\implies \frac{dr}{dt} =\frac{1}{2}\text{ meter per hour}

Now,

Volume of a cylinder,

V=\pi r^2 h

Differentiating w. r. t. t,

\frac{dV}{dt}=\pi ( r^2 \frac{dh}{dt}+h(2r)\frac{dr}{dt})=\pi ((3)(6) (\frac{1}{2})) = 9\pi \text{ cubic meters per hour}

6 0
3 years ago
The measure of c is?
Cloud [144]

<em>answer \\  \sqrt{208} \\  solution \\ hypotenuse = c \\ perpendicular = 8 \\ base = 12 \\ using \: pythagoras \: theorem \\  {h}^{2}  =  {p}^{2}  +  {b}^{2}  \\ or \:  {c}^{2}  =  {8}^{2}  +  {12}^{2}  \\ or \:  {c }^{2}  = 64 + 144 \\ or \:  {c}^{2}  = 208 \\ c =  \sqrt{208}  \\ hope \: it \: helps</em>

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3 years ago
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An equilateral triangle is similar to a scalene triangle. True or False
san4es73 [151]

Answer:

False.

Step-by-step explanation:

All the sides of an equilateral triangle are equal.

None of the sides of a scalene triangle are equal to each other.

Therefore, an equilateral triangle is <u>not</u><u> </u>similar to a scalene triangle.

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When constructing a confidence interval for a population mean, if a population is normally distributed and a small sample is tak
ddd [48]

Answer:

<h3>"When constructing a confidence interval for a population mean, if a population is normally distributed and a small sample is taken, then the distribution of is based on the <u> "t" </u>distribution</h3>

Step-by-step explanation:

Given that "When constructing a confidence interval for a population mean, if a population is normally distributed and a small sample is taken, then the distribution of is based on the "<u>t"</u>distribution."

Because the given sample size is smaller so we have to use the "t" distribution for constructing the confidence interval for a given population

6 0
3 years ago
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