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3 years ago

Of a company’s 85 employees, 60 work full time and 40 are married. Half of the fulltime workers are married.

Mathematics

1 answer:

zvonat [6]3 years ago

7 0

It is implied from the given conditions that

Unmarried employees = 45

Unmarried employees that work full time = 30

Part time working employees = 25

Unmarried employees that work part time = 15

Married employees that work part time = 10

Thus

The probability of a part time employee = 25/85

The probability of an unmarried employee = 45/85

Hence probability that an employee works part time or is not married = (25/85) + (45/85)

= (25 + 45) / 85

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CAN SOMEONE FACTOR THIS PLEASE <br><br> 125х^6 - 81

alexandr402 [8]

Answer:

Step-by-step explanation:

125×^6_81=0

×^6 we do not support this expression

ans = 0

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1 year ago

What is the length of the hypotenuse of a right triangle with legs of 50 ft. and 120 ft. ?

MrMuchimi

Answer: 130 ft

Step-by-step explanation:

a^2 + b^2 = c^2

Where a and b are the legs that form the right angle and c is the hypotenuse (the side directly opposite of the right angle)

50^2 + 120^2 = c ^2

2,500 + 14,400 = c^2

16,900 = c^2

Take the square root of 16,900 to get c.

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2 years ago

What is the angle, in degrees, if the Area is 180 square miles and the radius is 42,240 feet?

Savatey [412]

Step-by-step explanation:

the area of a circle (all 360°) is

pi×r²

with r being the radius.

the area of a circle segment is just the corresponding fraction of the whole circle.

so the area of a segment of x degrees is

pi×r² × x/360

in our case we know

pi×42240² × x/360 = 180 mi²

we also know that there are 5280 ft in 1 mile.

so, the radius is actually

42240 / 5280 = 8 miles

and therefore our equation resulting in mi² has to use miles and not ft and has to look that way :

pi×8² × x/360 = 180 mi²

pi×64 × x/360 = 180

pi×64 × x = 180×360

pi×x = 180×360/64 = 1012.5

x = 1012.5/pi = 322.2887598...°

so, the angle of the segment of a circle with the area of 180 mi² and the radius of 8 mi is 322.2887598...°

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2 years ago

Will mark Branliest! Need help ASAP

Neko [114]

Answer:

12/2

Step-by-step explanation:

An integer is neither a fraction nor a decimal, but in this case you can simplify 12/2 to 6 which is a whole number making it an integer. Hope you found this helpful!

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2 years ago

Read 2 more answers

A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.

pav-90 [236]

Answer:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.25$ represent the population standard deviation

n represent the sample size

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

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2 years ago