Answer:
2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3
Explanation:
First of all, let us balance the equation to give;
2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 3NaOH
Now, we can observe the presence of positive Sodium ions (Na+) and negative hydroxyl ions (OH-) on both left and right sides of the equation.
Now, the two ions will cancel out. These ions are not really involved in the overall reaction and thus do not require being written in the overall equation. Hence, the overall net ionic reaction can now be written as:
2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3
Answer:
13.33 g/dm³
Explanation:
Concentration (g/dm³)= mass(g) ÷ volume (dm³)
Now you need to convert 150 cm³ to dm³
1000cm³ = 1 dm³
thus, 150 cm3= 150 ÷ 1000
= 15dm³
and you already have mass in grams
so concentration = 2 ÷ 0.15
= 13.33 g/dm³ and there you go.. solved ;)
We are given that 1 teaspoon is equivalent to 5 mL,
therefore 0.75 teaspoon is:
0.75 teaspoon * (5 mL / 1 teaspoon) = 3.75 mL
So the mass is density times volume:
mass = (12.5 mg/5 ml) * 3.75 mL
<span>mass = 9.375 mg</span>
Answer:
For large rivers the problem is not simply a matter of deduction of consumptive use from runoff: it is more complex and the complexity is related to the changes in .
Explanation:
The answer is 3. As 5 * 3 = 15.
Is there any other equations I may be able to help you with? :)
