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Lera25 [3.4K]
3 years ago
13

Could anyone give me the answer to this plz 20 points

Chemistry
1 answer:
svetoff [14.1K]3 years ago
6 0
13 - Periodic table
14 - Dimitri mandeleev
15 - groups


Mark me brainiest pls it right answer
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Explain why gasoline is a mixture
Makovka662 [10]

Explanation:

Gasoline has many different types of hydrocarbons. This makes it a mixture.

3 0
3 years ago
Calculate the mass of arsenic(III) chloride produced when 0.150 g of arsenic reacts with excess chlorine according to the equati
adell [148]

Answer:

0.363 g

Explanation:

2As + 3Cl₂      →   2AsCl₃

calculate the number of moles of arsenic

Number of moles = mass/ molar mass

Number of moles =  0.150 g/ 75 g/mol

Number of moles = 0.002 mol

compare the moles of arsenic with arsenic chloride.

                         As             :             AsCl₃

                          2              :                2

                        0.002        :              0.002

Mass of arsenic chloride produced:

Mass = number of  moles × molar mass

Mass = 0.002 × 181.28 g/mol

Mass = 0.363 g

6 0
3 years ago
Which statement is true of a heterogeneous mixture but not of a
Natalka [10]

Answer:

B

Explanation:

well heterogenous mixtures are not uniformly distributed these meaning whatever components are "mixed" can be seperated easily

a example of this can be

Soil, oil in water, ice in water

while Homogeneous mixture cannot be seen seperated

4 0
3 years ago
Aqueous acetic acid is neutralized by aqueous potassium hydroxide. True or False
liberstina [14]

Answer:

i think its true but I’m not sure

Explanation:

I know that they can. Be mixed

4 0
3 years ago
Read 2 more answers
The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a
Rudiy27

Answer:

The amount left after 49.2 years is 3mg.

Explanation:

Given data:

Half life of tritium = 12.3 years

Total mass pf tritium = 48.0 mg

Mass remain after 49.2 years = ?

Solution:

First of all we will calculate the number of half lives.

Number of half lives = T elapsed/ half life

Number of half lives =  49.2 years /12.3 years

Number of half lives =  4

Now we will calculate the amount left after 49.2 years.

At time zero 48.0 mg

At first half life = 48.0mg/2 = 24 mg

At second half life = 24mg/2 = 12 mg

At 3rd half life = 12 mg/2 = 6 mg

At 4th half life =  6mg/2 = 3mg

The amount left after 49.2 years is 3mg.

6 0
4 years ago
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