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lesantik [10]
3 years ago
5

Find the circumference of a circle with diameter 7.3 m Use the pi key on your calculator and round your answer to the nearest te

nth
Mathematics
1 answer:
Crank3 years ago
4 0

Answer:

22.9 m

Step-by-step explanation:

Circumference = π × diameter

Using a calculator to evaluate 7.3π, we get 22.933626...

Rounding this to the nearest tenth gives 22.9. Units are meters.

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Find the area of each shape
a_sh-v [17]
The square is 130 in squared and the other shape is 54 in squared. If you're looking for the sum of the whole thing, its 185 in squared.
square: 13*10=130
triangle: 7*4= 28/2=14
rectangle: 10*4=40
5 0
3 years ago
Please answer math questionS correctly for BRAINY
agasfer [191]
Hello there,

1st attachment: 

So in order to find this answer. We need to know that in a CUBE there is L*W*H. Your answer would be A.) 1125 because when we do 1125 3 times (L*W*H). . . It give's us 3375.

2nd attachment:

Your answer would be D.) 5,832m³.

My reason I say this is because when you do 18 square root to 3. It will give you 5,832m³

3rd attachment:

Your correct answer would be 80mm³. So this is what I did. C wouldn't be the wrong answer because that answer is in "inches" and we want to find the answer in "mm³" So when we do 2*2*2. We get 8cm. We need to find the answer in "mm³" "8cm" converted in "mm³" would equal 80mm³.

Hope this helps.

~Jurgen

4 0
3 years ago
Read 2 more answers
Drawing a 2, then drawing another 2?
iren2701 [21]

Answer:

it it two

Step-by-step explanation:

5 0
3 years ago
(5ab-9a-4) - (-4ab + 5)
qaws [65]

Answer:

9ab - 9a +1

Step-by-step explanation:

first, we can distribute the negative sign to the second set of parentheses.

-(-4ab + 5) becomes + 4ab - 5

now let's put the values in (5ab-9a-4) side by side with the corresponding values in + 4ab - 5

5ab + 4ab - 9a - 4 - 5

= 9ab - 9a - 9, because 5ab + 4ab = 9ab, -9a is alone, and -4 - 5 = -9.

8 0
3 years ago
Prove that the sum of the squares of any two odd numbers is always even
ValentinkaMS [17]

Answer:

proof below

Step-by-step explanation:

Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)

Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;

(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2

= 2(2a^2 + 2a + 2b^2 + 2b + 1)

Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.

6 0
3 years ago
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