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3 years ago

Which equation of a circle is represented by the graph?

Mathematics

1 answer:

Sedbober [7]3 years ago

6 0

Answer:

$x^2+y^2=25$

Step-by-step explanation:

The given circle is centered at the origin;

The radius of the circle is

$r=|5-0|=5$ units.

You could also count the boxes from the center to any of the given points to get the radius.

The equation of a circle centered at the origin is given by;

$x^2+y^2=r^2$

We substitute the radius to obtain;

$x^2+y^2=5^2$

The required equation is

$x^2+y^2=25$

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Norma-Jean [14]

Answer:

Therefore surface integral is $\pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c$ .

Step-by-step explanation:

Given function is,

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$\int\int_{S}\vec{F}dS$

where S=A=surfece of elliptic cylinder we have to apply Divergence theorem so that,

$\int\int_{S}\vec{F}dS$

$=\int\int\int_V\nabla.\vec{F}dV$

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$=\frac{a^2+b^2}{ab}\times \textit{Volume of the elliptic cylinder}$

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If unit vector $\cap{n}$ directed in positive (outward) direction then z=c and,

$\int\int_{S_1}\vex{F}.dS_1=\int\int_{S_1} . dA$

$=\int\int_{S_1}.dA=0$

If unit vector $\cap{n}$ directed in negative (inward) direction then z=-c and,

$\int\int_{S_2}\vex{F}.dS_2=\int\int_{S_2}. -dA$

$=\int\int_{S_2}. -dA=0$

Therefore surface integral without unit vector of the surface is,

$\pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c$

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4 years ago

Given xy = 4 and x2 + y2 = a, which expression is equal to (x + y)2? a + 6 a + 8 a + 4

likoan [24]

Answer:

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Step-by-step explanation:

Note that

(x + y)² = x² + 2xy + y²

= x² + y² + 2xy

= a + 2(4) = a + 8

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3 years ago

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Natalka [10]

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