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Masja [62]
3 years ago
11

The force of gravity acting on a child's mass on earth is 490 newtons. What's the child's mass? A. 206 kg B. 4,802 kg C. 50 kg D

. 800 kg
Physics
2 answers:
Gnoma [55]3 years ago
6 0
The answer is C. 50 kg because:

F = mxa
M = f/a
= 490N/9.81m/s^2
= 50kg

Ksju [112]3 years ago
4 0
The child's mass on earth is equal to 50kg.
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A 0.5 kg block is attached to a spring (k = 12.5 N/m). The damped frequency is 0.2% lower than the natural frequency, (a) What i
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Answer:

a)  1.58 kg s^{-1}

b)  x_m e^{-1.58t}   x_m is initial amplitude

c) 5 kg s^{-1}

Explanation:

given data:

mass =0.5 kg

k = 12.5 N/m

from the data given

a) w_d = w_o - \frac{0.2}{100}w_o

= w_o - 0.002w_o = 0.99w_o

w_d = \sqrt{\frac{k}{m} - \frac{b^2}{4m^2}

0.998w_o = \sqrt{w_o^2 - \frac{b^2}{4m^2}

(0.998w_o)^2 = w_o^2 -\frac{b^2}{1}

b^2 = w_o^2 -(0.998w_o)^2

b^2 = w_o^2(1-0.998^2) = 3.996 *10^{-3} w_o^2

b = w_o\sqrt{3.996*10^{-3}}

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b)x = x_m e^{\frac{-bt}{2m}}

   x = x_m e^{-1.58t}{1} = x_m e^{-1.58t}    where x_m is initial amplitude

c) critical damping amplitude

c_c =2\sqrt{km} = 2\sqrt{12.5*.5} = 5 kg s^{-1}

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