the amount of heat need is 71060 Joules
ExplanationThe equation for the amount of heat needed to increase the temperature of water is as follows:
where E is the amount of heat
C is the specific heat capacity of water having a standard value of 4180 J/kg*K
T is the final ans initial temperature in kelvin
m is the mass
so
Step 1
given
a) convert the temperature into kelvin
now, replace in the formula
therefore, the amount of heat need is 71060 Joules
I hope this helps you
Answer:
acceleration = 2.4525 m/s²
Explanation:
Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²
Tension in the rope = T
Sol: m2 > m1
i) for downward motion of m2:
m2 a = m2 g - T
5 a = 5 × 9.81 m/s² - T
⇒ T = 49.05 m/s² - 5 a Eqn (a)
ii) for upward motion of m1
m a = T - m1 g
3 a = T - 3 × 9.8 m/s²
⇒ T = 3 a + 29.43 m/s² Eqn (b)
Equating Eqn (a) and(b)
49.05 m/s² - 5 a = T = 3 a + 29.43 m/s²
49.05 m/s² - 29.43 m/s² = 3 a + 5 a
19.62 m/s² = 8 a
⇒ a = 2.4525 m/s²
Answer:
-2.79 x 10²J
Explanation:
using the pressure volume work formula which states that
work = -PΔV
= -(1.0 atm) (2.7-0.0)L = -2.7L . atm
Convert litre.atmosphere to Joules.
1 L . atm = 101.325 joules
-2.75 L .atm = -2.75 x 101.325 = -278.64375 =
Work = -2.79 x 10²J
Answer:
The collision is not elastic. The system increases his kinetic energy m*v₀² times.
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved.
Considering the information provided, we can write the momentum conservation equation as follows:
m*v₀ = -m*v₀ + 2*m*vf
Solving for vf, we arrive to this somehow surprising result:
vf = v₀ (in the same direction that m was moving before the collision).
In order to determine if the collision was elastic, or not, we need to calculate the kinetic energy of the system before and after the collision:
K₀ = 1/2*m*v₀²
Kf = 1/2*m*v₀² (due to the object of mass m, as the kinetic energy is always positive) + 1/2 (2m) * v₀²
⇒Kf = 1/2*m*v₀² + 1/2 (2m) * v₀² = 3/2*m*v₀²
ΔK = Kf - K₀ = 3/2*m*v₀² - 1/2*m*v₀² = m*v₀²
As there is a net difference between the final and initial kinetic energies, and the total kinetic energy must be conserved in an elastic collision (by definition) we conclude that the collision is not elastic, and the change in the kinetic energy of the system is equal to m*v₀².
