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3 years ago

15

I mostly know how to do these vector problems i’m just confused on how many decimal places i use

2 answers:

Firlakuza [10]3 years ago

7 0

significant figures rules!! since all of the problems use 2 sig figs, you would make your answer 2 as well.

Degger [83]3 years ago

5 0

I believe you use 4? I’m really unsure about that but I like your Joy Division picture

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It is night. Someone who is 4 feet tall is walking away from a street light at a rate of 8 feet per second. The street light is

KiRa [710]

Answer: 4 ft/s

Explanation:

Given

height of man $=4 ft$

speed of person $v=8 ft/s$

height if street light $=12 ft$

Let x be the distance between person and street light and y be the length of his shadow

From diagram

as the two triangle ADE and ABC are similar therefore we can say that

$\frac{4}{12}=\frac{y}{x+y}$

$\frac{1}{3}=\frac{y}{x+y}$

$x+y=3y$

$x=2y$

differentiate above Equation w.r.t time we get

$\frac{\mathrm{d} x}{\mathrm{d} t}=2\frac{\mathrm{d} y}{\mathrm{d} t}$

$\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{8}{2}=4 ft/s$

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2 years ago

How do I find magnitude of acceleration?

Leno4ka [110]

Divide the change in speed by the time for the change.

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2 years ago

Sanjay is making plans for his Saturday afternoon. He can choose a health-enhancing activity like lifting weights, or he can cho

Bezzdna [24]

Answer: Sanjay can burn 100 more calories every 30 minutes if he chooses to lift weights instead of watching tv

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2 years ago

Why are latitude and longitude included on maps

Veseljchak [2.6K]

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2 years ago

A high power line carries a current of 1.0 kA. What is the strength of the magnetic field this line produces at the ground, 10 m

solmaris [256]

Answer:

The strength of the magnetic field that the line produces is $2x10^{-5} Tesla$ .

Explanation:

From Biot-Savart law, the equation to determine the strength of the magnetic field for any straight wire can be deduced:

$B = \frac{\mu_{0}I}{2\pi r}$ (1)

Where $\mu_{0}$ is the permiability constant, I is the current and r is the distance from the wire.

Notice that it is necessary to express the current, I, from kiloampere to ampere.

$I = 1.0kA \cdot \frac{1000A}{1kA}$ ⇒ $1000A$

Finally, equation 1 can be used:

$B = \frac{(4\pi x10^{-7}T.m/A)(1000A)}{2\pi (10m)}$

$B = 2x10^{-5}T$

Hence, the strength of the magnetic field that the line produces is $2x10^{-5} Tesla$ .

8 0

2 years ago