<u>Given:</u>
Volume of air inhaled V = 0.56 L
Temperature T = 37 C = 37 +273 = 310 K
Pressure P = 744 mmHg = 744/760 = 0.979 atm
% N2 in air = 78%
<u>To determine:</u>
The moles of N2 inhaled in one breath
<u>Explanation:</u>
Step 1: Calculate the moles of air inhales
Based on the ideal gas law:
PV = nRT
where P = pressure, T = temperature, V = volume, n = # moles
R = gas constant = 0.0821 L atm/mol-K
n = PV/RT = 0.979 * 0.56/0.0821*310 = 0.0215 moles of air
Step 2: Calculate the moles of N2
It is given that air contains 78% N2
Therefore:
moles of N2 = 0.0215 * 78/100 = 0.0168 moles
Ans: moles of N2 = 0.0168
