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Deffense [45]
3 years ago
13

The chemical equation below shows the reaction between carbon dioxide (CO2) and lithium hydroxide (LiOH). CO2 + 2LiOH mc011-1.jp

g Li2CO3 + H2O The molar mass CO2 is 44.01 g/mol. How many moles of LiOH are needed to react completely with 25.5 g of CO2?
Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
5 0
From the given balanced chemical equation,
                            CO2 + 2LiOH --> Li2CO3 + H2O
we can conclude that for every 2 moles of LiOH, we need a mole of CO2. Calculate first the number of moles of CO2 by dividing the given mass by the molar mass giving us an answer of 0.58 moles. Using proportionality,
                             0.58 / x = 1 / 2
The value of x is equal to 1.16 moles. 
ser-zykov [4K]3 years ago
3 0

Answer:

C

Explanation:

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Consider two concentric spheres whose radii differ by t = 1 nm, the "thickness" of the interface. At what radius (in nm) of sphe
Gala2k [10]

Answer:

Radius of the interior sphere = 3.847 nm

Explanation:

The volume of the shell (Vs) is equal to the difference of the volume of the outer sphere (Vo) and the volume of the inner sphere (Vi). Then:

V_s=V_o-V_i=V_i\\V_o=2*V_i\\

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r_o=r_i+e

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\frac{4 \pi}{3}*r_o^{3}  = 2 * \frac{4 \pi}{3}*r_i^{3}  \\\\\frac{4 \pi}{3}*(r_i+e)^{3}  = 2 * \frac{4 \pi}{3}*r_i^{3}  \\\\(r_i+e)^{3}  = 2 *r_i^{3}  \\\\(r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3})=2r_i^{3}\\\\-r_i^{3}+3r_i^{2}e+3r_ie^{2}+e^{3}=0\\\\-r_i^{3}+3r_i^{2}+3r_i+1=0

To find ri that satisfies this equation we have to find the roots of the polynomial.

Numerically, it could be calculated that ri=3.847 nm satisfies the equation.

So if the radius of the interior sphere is 3.847 nm, the volume of the interior sphere is equal to the volume of the shell of 1nm.

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