Answer: chemistry is love ❤️ #bae
Explanation: ok just kidding. The dictionary says chemistry is the scientific discipline with elements and compounds of atoms, molecules, and ions
Answer:
ΔG = 18KJ/mol
Explanation:
Given data:
ΔS = 0.09 Kj/mol.K
ΔH = 27 KJ/mol
Temperature = 100 K
ΔG = ?
Solution:
Formula:
ΔG = ΔH - TΔS
ΔH = enthalpy
ΔS = entropy
by putting values,
ΔG = 27 KJ/mol - 100K(0.09 Kj/mol.K)
ΔG = 27 KJ/mol - 9 KJ/mol
ΔG = 18KJ/mol
The combustion of an organic compound is mostly written as,
CaHbOc + O2 --> CO2 + H2O
where a, b, and c are supposed to be the subscripts of the elements C, H, and O in the compound. Determining the number of moles of C and H in the product which is the same as that in the compound,
(Carbon, C) : (561 mg) x (12/44) = 153 mg x (1 mmole/12 mg) = 12.75
(Hydrogen, H) : (306 mg) x (2/18) = 34 mg x (1 mmole/1 mg) = 34
Calculating for amount of O in the sample,
(oxygen, O) = 255 - 153 mg - 34 mg = 68 mg x (1mmole/16 mg) = 4.25
The empirical formula is therefore,
C(51/4)H34O17/4
C3H8O1
The molar mass of the empirical formula is 60. Therefore, the molecular formula of the compound is,
C9H24O3
<span>This would be the activation energy. This is usually in the form of heat, which allows the reaction to undergo some sort of transition. Many times, enzymes can be used as catalysts to lower the activation energy required for the reaction to take place.</span>
Hrxn = Q reaction / mol of reaction
mol of reaction = M * V = 10 * 1 = 10 mmol = 0.01 mol
Q water = m * C * (Tf - Ti)
= (10 + 10) (4.184) (26-20) = 502.08 J
Q reaction = - Q water = -502.08 J
Hrxn = -502.08 / (0.01) = - 50208 J = - 50.21 kJ/mol
