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sergejj [24]
3 years ago
11

What is 19 hundred thousandths in scientific notation

Chemistry
2 answers:
Drupady [299]3 years ago
8 0
.00019 

ignore
Too short of an answer /20chars
frosja888 [35]3 years ago
3 0
0.0019 = 1.9 * 10^-3
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A 4-inch, f/5 telescope has a 1-inch eyepiece focal. Its magnifying power is:
Gre4nikov [31]

Its magnifying power is: 4X 5X 9X 20X. A 4-inch, f/5 telescope has a 1-inch eyepiece focal. Its magnifying power is 9x. This answer has been confirmed as correct and helpful.

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3 years ago
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Which is a polar molecule?
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3 years ago
How many moles of gold are equivalent to 1.204 × 1024 atoms?
LUCKY_DIMON [66]

Explanation:

It is known that the value of Avogadro's number is 6.022 \times 10^{23}.

Therefore, calculate moles of gold atoms as follows.

    Moles of gold atom = \frac{given number of atoms}{Avogadro's number}

                                    = \frac{1.204 \times 10^{24}}{6.022 \times 10^{23}mol^{-1}}

                                    = 0.199 \times 10 mol

                                    = 1.99 mol

Thus, we can conclude that 1.99 mol of gold atoms are equivalent to 1.204 \times 10^{24} atoms.

7 0
2 years ago
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A 0.2121g sample of an organic compound was burned in a stream of oxygen and the carbon dioxide produced was collected in a stre
pav-90 [236]

Answer:

The answer to your question is: 17.26% of carbon

Explanation:

Data

CxHy = 0.2121 g

BaCO₃ = 0.6006 g

Molecular mass BaCO₃ = 137 + 12 + 48 = 197 g

Reaction

                    CO₂  +  Ba(OH)₂  ⇒   BaCO₃  +  H₂O

Process

1.- Find the amount of carbon in BaCO₃

                              197 g of BaCO₃   ---------------  12 g of Carbon

                               0.6006 g           ----------------    x

                               x = (0.6006 x 12) / 197

                               x = 0.0366 g of carbon

2.- Calculate the percentage of carbon in the organic compound

           0.2121 g of organic compound  ---------------  100%

           0.0366g                                       --------------    x

                              x = (0.0366 x 100) / 0.2121

                              x = 17.26%

4 0
2 years ago
How many molecules of H3PO4 are in 125 g of H3PO4
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Answer:

2.11 * 10^3 molecules of phosphoric acid

Explanation:

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