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3 years ago

Ionization Energy Question please help

Chemistry

1 answer:

Nezavi [6.7K]3 years ago

8 0

Answer:

Element will be in group 2. Charge will be +2.

Explanation:

This is because the difference of the ionization energy is the biggest between the 2nd IE and the 3rd IE. When you see the biggest difference, that indicates the last electron left on that shell. So, there are 2 electrons in the outer shell, therefore group 2.

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What is the pH of a substance that has a hydrogen ion concentration of<br> 8.8x10^(-5) M? *

stealth61 [152]

Answer:

The pH of the substance is 4,06.

Explanation:

The pH indicates the acidity or basicity of a substance. PH values between 0 and less than 7 indicate acidic solutions, 7 neutral and greater than 7 to 14 basic. It is calculated as:

pH = -log (H +)

pH= -log (8.8x10^-5)

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3 years ago

Your friend the archaeologist, who studies the ancient human past, has asked you to find a numerical date for some hominid artif

natulia [17]

Answer:

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3 years ago

Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess

Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, $K_c=3.6243\times 10^{3}$ .

Explanation:

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

The relation of $K_c\& K_p$ is given by:

$K_p=K_c(RT)^{\Delta n_g}$

$K_p$ = Equilibrium constant in terms of partial pressure.=98.1

$K_c$ = Equilibrium constant in terms of concentration =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

$\Delta n_g$ = Difference between gaseous moles on product side and reactant side= $n_{g,p}-n_{g.r}=1-2=-1$

$98.1=K_c(RT)^{-1}$

$98.1 =\frac{K_c}{RT}$

$K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}$

The equilibrium constant in terms of concentration that is, $K_c=3.6243\times 10^{3}$ .

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3 years ago

Read 2 more answers

From top to bottom in most groups of elements, atomic radii tend to A. decrease because the nuclear charge increases. B. decreas

Stels [109]

D. As more electrons are added to an element, the number of electron orbitals being filled increases

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3 years ago

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If 65.5 moles of an ideal gas is at 9.15 atm at 50.30 °C, what is the volume of the gas?

qwelly [4]

To calculate for the volume, we need a relation to relate the number of moles (n), pressure (P), and temperature (T) with volume (V). For simplification, we assume the gas is an ideal gas. So, we use PV=nRT.

PV = nRT where R is the universal gas constant
V = nRT / P
V = 65.5 ( 0.08205 ) (273.15 + 50.30) / 9.15
V = 189.98 L

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4 years ago