1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LuckyWell [14K]
2 years ago
14

What mass of CCl4 is formed by the reaction of 5.14 g of methane with an excess of chlorine?

Chemistry
2 answers:
NeTakaya2 years ago
8 0

\boxed{{\text{49}}{\text{.224 g}}} of {\text{CC}}{{\text{l}}_4} is produced by the reaction of 5.14 g of methane with an excess of chlorine.

Further explanation:

Stoichiometry of a reaction is used to determine the amount of species present in the reaction by the relationship between the reactants and products. It can be used to determine the moles of a chemical species when the moles of other chemical species present in the reaction is given.

Consider the general reaction,

{\text{A}} + 2{\text{B}}\to3{\text{C}}

Here,

A and B are reactants.

C is the product.

One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.

Limiting reagent:

A limiting reagent is the one that is completely consumed in a chemical reaction. The amount of product formed in any chemical reaction has to be in accordance with the limiting reagent of the reaction. The amount of product depends on the amount of limiting reagent since the product formation is not possible in the absence of it.

The given reaction occurs as follows:

{\text{C}}{{\text{H}}_4}\left(g\right) + 4{\text{C}}{{\text{l}}_2}\left(g\right)\to{\text{CC}}{{\text{l}}_4}\left(g\right)+4{\text{HCl}}\left(g\right)

It is given that chlorine is present in an excess amount so methane \left({{\text{C}}{{\text{H}}_4}}\right) is a limiting reagent and therefore it controls the amount of {\text{CC}}{{\text{l}}_4}  produced during the reaction.

The formula to calculate the amount of {\text{C}}{{\text{H}}_4}  is as follows:

{\text{Amount of C}}{{\text{H}}_4} = \frac{{{\text{Given mass of C}}{{\text{H}}_{\text{4}}}}}{{{\text{Molar mass of C}}{{\text{H}}_{\text{4}}}}}                  …… (1)

The given mass of {\text{C}}{{\text{H}}_4}  is 5.14 g.

The molar mass of {\text{C}}{{\text{H}}_4}  is 16.04 g/mol.

Substitute these values in equation (1).

\begin{aligned}{\text{Amount of C}}{{\text{H}}_4} &= \left({{\text{5}}{\text{.14 g}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{16}}{\text{.04 g}}}}}\right)\\ &= 0.32044\\&\approx{\mathbf{0}}{\mathbf{.320 mol}}\\\end{aligned}

From the balanced chemical reaction, it is clear that 1 mole of {\text{C}}{{\text{H}}_4} produces 1 mole of {\text{CC}}{{\text{l}}_4} .

So the amount of {\text{CC}}{{\text{l}}_4}  is equal to that of {\text{C}}{{\text{H}}_4}  and thus the amount of {\text{CC}}{{\text{l}}_4}  is 0.320 mol.

The formula to calculate the mass of  {\text{CC}}{{\text{l}}_4} is as follows:

{\text{Mass of CC}}{{\text{l}}_4} = \left( {{\text{Moles of CC}}{{\text{l}}_4}}\right)\left({{\text{Molar mass of CC}}{{\text{l}}_4}}\right)

…… (2)

The number of moles of {\text{CC}}{{\text{l}}_4}  is 0.320 mol.

The molar mass of {\text{CC}}{{\text{l}}_4}  is 153.82 g/mol.

Substitute these values in equation (2).

\begin{gathered}{\text{Mass of CC}}{{\text{l}}_4} = \left({{\text{0}}{\text{.320 mol}}}\right)\left({\frac{{{\text{153}}{\text{.82 g}}}}{{{\text{1 mol}}}}}\right)\\ = {\mathbf{49}}{\mathbf{.224 g}}\\\end{gathered}

Therefore, the mass of {\text{CC}}{{\text{l}}_4} produced is 49.224 g.

Learn more:

1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: <u>brainly.com/question/3064603 </u>

2. How many grams of potassium were in the fertilizer? <u>brainly.com/question/5105904 </u>

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: stoichiometry, reactant, product, limiting reagent, CCl4, CH4, Cl2, molar mass, given mass, amount of CH4, amount of CCl4, 49.224 g, mass of CCl4, 4Cl2, 4 HCl, 5.14 g, 16.04 g/mol.

myrzilka [38]2 years ago
6 0
Because CH4 is the limiting reagent, we must find how many moles we have.
1. 5.14 g CH4 * (1 mol CH4 / 16.04 g/mol) = .32125 moles CH4
Now we know that there are .32125 moles of CCl4 produced as well.
Next, take .32125 moles and multiply it by the atomic mass of CCl4, which is 153.82 grams = 49.29 g CCl4 produced by the reaction.
You might be interested in
In a previous problem, the empirical formula of a compound of phosphorus and oxygen was found to be p2o5. experimentation shows
agasfer [191]
The empirical formula for the compound is - P₂O₅
the empirical formula is the simplest ratio of whole numbers of components in a compound.
molecular formula is the actual ratio of components in a compound.
we have to first find the number of empirical units in the molecular formula 
molecular mass - 283.89 g/mol
mass of empirical formula - 283.8 g
number of empirical units - 283.89 g/mol / 283.8 g
number of empirical units - 1.000 
therefore empirical formula = molecular formula 
molecular formula - P₂O₅
3 0
3 years ago
element m is a metal and its chloride has the formula mcl2. to which group of the periodic table does m most likely belong
Triss [41]
It will belong to the metals because metals bond with nonmetals like chlorine to form ionic compounds
3 0
2 years ago
Read 2 more answers
g This plot shows the rate of the decomposition of SO2Cl2 into SO2 and Cl2 as a function of the concentration of SO2Cl2. What is
scoundrel [369]

Answer:

When n = 1, the reaction is of the First Order

Explanation:

Find attach the solution

5 0
3 years ago
2c8h18(g 25o2(g→16co2(g 18h2o(g how many moles of water are produced in this reaction
AleksandrR [38]
18 moles of water are produced in the above reaction.
Hope this helps you!
3 0
2 years ago
Read 2 more answers
The chemical equation, 2 Cr + 3 Fe(NO3)2 - 3 Fe + 2 Cr(NO3)3, is an
lana66690 [7]

Answer:

Single replacement reaction (aka single displacement reaction)

Explanation:

In a single replacement reaction, one element is substituted for another in a compound to create a new compound and a new element in the products. The general form is:

A + BC --> B + AC

In the case of this question, Cr and Fe "trade places."

6 0
2 years ago
Other questions:
  • Energy transfer by convection is usually restricted to what type of substance?
    15·1 answer
  • Find the theoretical probability of randomly choosing a vowel from the alphabet. 5/25 5/26 4/25 4/26
    9·1 answer
  • In group 14 which is a metalloid
    10·1 answer
  • Two representations of the distribution of electrons in the potassium atom are shown. Model 1 Model 2 1s22s22p63s23p64s1 An oran
    10·2 answers
  • Briefly explain the observed effect of the acetylcholine concentration on the rate of the enzyme-catalyzed reaction
    6·1 answer
  • A graduated cylinder is filled with 50.7 mL of water. If a 10.0 g piece of zinc metal is added to the water, and the volume rise
    12·1 answer
  • Please help, this is due today. I will give brainliest
    12·1 answer
  • What is the formula of Barium Carbonate?​
    14·2 answers
  • What causes astronauts to appear to float in the space station?
    14·1 answer
  • Water is said to be a good solvent for polar solutes because it has a negative end and a positive end. This explains why (IONIC/
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!