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lilavasa [31]
3 years ago
11

Need answer now! 100 points

Chemistry
2 answers:
ratelena [41]3 years ago
5 0

Answer: D

divide the moles of the substances given in the question by the co-efficient in the equation. Smallest quotient is the limiting reactant

s344n2d4d5 [400]3 years ago
3 0

Answer:

D) HBr

Explanation:

Given data:

Number of moles of Al = 8 mol

Number of moles of HBr = 8 mol

Limiting reactant = ?

Solution:

2Al + 6HBr      →      2AlBr₃ + 3H₂

now we will compare the moles of reactants with products.

                Al          :         AlBr₃

                   2         :            2

                    8         :          8

                 Al           :          H₂

                 2             :          3

                 8             :           3/2×8 = 12

                 HBr         :         AlBr₃

                   6           :              2

                    8           :            2/6×8 = 2.67

                 HBr         :            H₂

                   6            :            3

                   8             :           3/6×8 = 4

HBr produced less number of moles of product thus it will act as limiting reactant.

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Explanation:

Hello there!

In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:

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Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:

1:

0=\Delta H-T\Delta S\\\\T=\frac{-102kJ/mol}{-0.188kJ/mol-K} \\\\T=542.55K

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It means that at temperatures higher than 660 K the reaction will be spontaneous.

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7 0
3 years ago
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