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SSSSS [86.1K]
3 years ago
14

Scenario: You are testing two different

Chemistry
2 answers:
chubhunter [2.5K]3 years ago
5 0

Answer:1 × 10-8 M

Explanation:

a_sh-v [17]3 years ago
5 0

Answer:

by a Factor of 10

Explanation:

Edge

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How many g NaOH should be required to completely react 1.876 g of Copper (II) nitrate?
Doss [256]

\\ \tt\hookrightarrow 2NaOH+Cu(NO_3)_2\longrightarrow 2NaNO_3+Cu(OH)_2

Moles of copper nitrate:-

\\ \tt\hookrightarrow \dfrac{1.876}{187.56}=0.001mol

  • 1mol of Copper nitrate reacts with 2mol NaOH
  • 0.001mol will react with 0.002mol NaOH

Madd of NaOH

\\ \tt\hookrightarrow 0.002(40)=0.08g

8 0
2 years ago
if we are made of stardust, does that make you feel more or less important as an individual (or just the same), and why?
melomori [17]
We Are Stardust—Literally. In this infrared image, stellar winds from a giant star cause interstellar dust to form ripples. There's a whole lot of dust—which contains oxygen, carbon, iron, nickel, and all the other elements—out there, and eventually some of it finds its way into our bodies.
7 0
4 years ago
Heat that flows by conduction is the transfer of thermal energy between substances in contact. What must occur for this
Lady bird [3.3K]

Heat flow by conduction requires that the two systems must not be touching each another.

<h3>What is heat energy?</h3>

Heat energy is a form of energy that exists due to a temperature difference between two objects.

Heat energy flows from an object at higher temperature to an object at a lower temperature.

Heat transfer by conduction involves the vibration of particles of the medium transferring heat due to contact between the two objects.

Therefore, heat flow by conduction requires that the two systems must not be touching each another.

Learn more about heat conduction at: brainly.com/question/893656

#SPJ1

7 0
2 years ago
Read 2 more answers
An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +
Maurinko [17]

Answer:

The simplified expression for the fraction  is  \text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3 }

Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
4 years ago
Which phase change is an example of an exothermic process?
liberstina [14]

its solid to liquid


5 0
3 years ago
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