Give the expected organic product when 3-phenylpropanoic, PhCH2CH2COOH , is treated with NaOH, H20 .If more than one product is
possible, only draw the major product.Include counter-ions, e.g., Na+, I-, in your submission, but draw them in their own separate sketcher.Separate structures with + signs from the dropdown menu.
1 answer:
Answer:
when 3-phenylpropanoic, PhCH₂CH₂COOH , is treated with NaOH, H₂0 it produce sodium salt of 3 - phenylpropanoic acid with water as a major product.
Explanation:
Carboxylic acid when treated with a base like NaOH or KOH gives carboxylate ion because H⁺ from acid reacts with OH⁻ from base gives H₂0 and salt of sodium carboxylate.
The mechanism of the above reaction given below
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Unfortunately you did not specify the electronic configuration in the question, however since one of the answers must be a halogen, i took the liberty to attach an image with the configuration (both the simple numeric and spdf form) for all the halogen and all you have to do is match the electronic configuration you have in your question to the one in the table attached and you can then deduce the answer.
Hope this helps.
Hope this helps.