Answer:
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Give the expected organic product when 3-phenylpropanoic, PhCH2CH2COOH , is treated with NaOH, H20 .If more than one product is
possible, only draw the major product.Include counter-ions, e.g., Na+, I-, in your submission, but draw them in their own separate sketcher.Separate structures with + signs from the dropdown menu.
1 answer:
Answer:
when 3-phenylpropanoic, PhCH₂CH₂COOH , is treated with NaOH, H₂0 it produce sodium salt of 3 - phenylpropanoic acid with water as a major product.
Explanation:
Carboxylic acid when treated with a base like NaOH or KOH gives carboxylate ion because H⁺ from acid reacts with OH⁻ from base gives H₂0 and salt of sodium carboxylate.
The mechanism of the above reaction given below
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Answer:
Explanation:
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In this case, since the rms speed of the molecules is computed by:
Whereas the absolute temperature is computed from the internal energy (by using the Cp of helium (3.1156 J/g*K) as shown below:
Thereby, the rms speed results:
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Answer:
0.1832 moles of ethyl acetate ()
Explanation:
1. Find the balanced chemical equation:
In the production of ethyl acetate, the acetic acid reacts with ethanol to produce ethyl acetate
and water, that is:
2. Find the theoretical maximum moles of ethyl acetate :
As the problem says that the acetic acid is the limiting reagent, use stoichiometry to find the moles of ethyl acetate produced: