Answer:
C) non renewable resources
Explanation:
These are resources such as oil that are formed over a long period of time but are consumed very quickly.
Answer:
a. There are only 5 electrons in 2p. 2p should be filled with 6 electrons prior to 3s and 3p
b. There are 8 electrons in 2p. 2p should be filled only with 6 electrons (not 8)
Explanation:
The typical electron configuration: 1s2 2s2 2p6 3s2 3p6
a. There are only 5 electrons in 2p
=> should be 1s2 2s2 2p6 3s2 3p2
b. There are 8 electrons in 2p
=> should be 1s2 2s2 2p6 3s2 3p1
Answer:
Explanation:
Li+H2O..................LiOH+H2
mass of Li=17.8 g
No of moles of Li=17.8/7=2.5
mass of H2O=50.0 g
No of moles of H2O=50.0/18=2.8
limiting reagent is Li so 1 mole of Li produce 1 mole of LiOH therefore 2.5 mole of Li produce 2.5 moles of LiOH now we have to convert it into grams
moles=given mass/molar mass
given mass=moles*molar mass
molar mass of LiOH=24
mass=2.5*24=60 gram
Answer:
(a) 0.8 s
(b) t = 7.2 s
Explanation:
(a) Half life expression for second order kinetic is:
![t_{1/2}=\frac{1}{k[A_o]}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7Bk%5BA_o%5D%7D)
Where,
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
is the initial concentration = 1.0 M
k is the rate constant = 1.25 M⁻¹s⁻¹
So,
Half life = 0.8 s
(b) Integrated rate law for second order kinetic is:
![\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA_t%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B%5BA%5D_0%7D%2Bkt)
Where, ![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the final initial concentration
For 90% completion, 10% is left. so,
![[A_t]=\frac {10}{100}\times 1.0=0.1\ M](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5Cfrac%20%7B10%7D%7B100%7D%5Ctimes%201.0%3D0.1%5C%20M)
So,
t = 7.2 s
2. B because it has a lower activation energy.
idk because you have no picture with the lines on it
