The answer to the question is B
Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
1 solution
Step-by-step explanation:
y = 1/2x + 4
x + 2y = -8
Solve the second equation for y.
2y = -x - 8
y = -1/2x - 4
The two equations in slope-intercept form are:
y = 1/2x + 4
y = -1/2x - 4
The system consists of two lines with different slopes, so they intercept at a single point which is the solution.
Answer: 1 solution
Answer:
w=7.
Step-by-step explanation:
Divide 7 on both sides of the equation.
Answer: -4
Step-by-step explanation:
2.5x = -10
1. divide -10 by 2.5
2. x = -4
