The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
Angle A is 64 degrees
Step-by-step explanation:
See attachment
Answer:
3 1/3 km or 3.33 km (to the hundredth)
Step-by-step explanation:
Using the given formula,
estimated distance = v.t = velocity * time,
velocity = 5 km/h
time = 40 minutes = 
hours = 
hours
Therefore
distance = 5 km/h * 
hours = 10/3 km
= 3.33 km approximately
