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3 years ago

What is (1-7x)(1+9x)

Mathematics

2 answers:

Vikentia [17]3 years ago

7 0

Answer:

1+2x-63x^2

Step-by-step explanation:

factor 1(1+9x)=1+9X

-7x(1+9x)=-7x-63x^2

add 1+9x-7x-63x2

Sveta_85 [38]3 years ago

5 0

ANSWER

$(1-7x)(1+9x) =- 63 {x}^{2} + 2x + 1$

EXPLANATION

The given product is (1-7x)(1+9x).

Expand using the distributive property.

$(1-7x)(1+9x) = 1(1 + 9x) - 7x(1 + 9x)$

$(1-7x)(1+9x) = 1 + 9x - 7x - 63 {x}^{2}$

Simplify to obtain:

$(1-7x)(1+9x) = 1 + 2x - 63 {x}^{2}$

You can rewrite in standard form to get,

$(1-7x)(1+9x) =- 63 {x}^{2} + 2x + 1$

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Growth rate problem that has a growth rate proportional to the population size can be solved using the equation:

P(t) = P₀eʳᵗ

t is your unit of time. It could be days, or hours, or minutes. It changes depending on each problem. In this problem, t is measured in years because you're jumping from 2000 to 2025. Years just makes the most sense to measure that leap in time.

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P₀ is the initial population at P(0)
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Now that everything is set out, lets use the equation to solve for our answer.

P(t) = P₀eʳᵗ

Australia:

$P(t)=(19169000)e^{(0.006)t}$

after 25 years

$P(25)=(19169000)e^{(0.006)(25)}=22271200.6$

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after 25 years:

$P(25)=(1261832000)e^{(.009)(25)}=1580220878$

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after 25 years:

$P(25)=(100350000)e^{(0.018)(25)}=157380127.8$

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after 25 years:

$P(25)=(51965000)e^{(0.031)(25)}=112794819.9$

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