Answer:
The concentration of the solution is 2.86 M
Explanation:
Molarity is a unit of concentration based on the volume of a solution. It is defined as the number of moles of solute that are dissolved in a given volume. In other words, molarity is defined as the number of moles of solute per liter of solution.
The Molarity of a solution is determined by the following expression:
![Molarity (M)=\frac{number of moles of solute}{Volume}](https://tex.z-dn.net/?f=Molarity%20%28M%29%3D%5Cfrac%7Bnumber%20of%20moles%20of%20solute%7D%7BVolume%7D)
Molarity is expressed in units (
).
In this case, you must then know the number of moles of HF, for which you must know the molar mass. Being:
the molar mass of HF is: HF= 1 g/mole + 19 g/mole= 20 g/mole
Then the following rule of three applies: if 20 g of HF are available in 1 mole, 14.3 g in how many moles will they be?
![moles=\frac{14.3 g*1 mole}{20 g}](https://tex.z-dn.net/?f=moles%3D%5Cfrac%7B14.3%20g%2A1%20mole%7D%7B20%20g%7D)
moles= 0.715
So:
- number of moles of solute: 0.715 moles
- Volume: 250 mL=0.250 L (being 1 L=1000 mL)
Replacing:
![Molarity=\frac{0.715 moles}{0.250 L}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7B0.715%20moles%7D%7B0.250%20L%7D)
Solving:
Molarity= 2.86
=2.86 M
<u><em>The concentration of the solution is 2.86 M</em></u>
The frequency of radio waves at the two stations are:
1. WIL-92.3 : Frequency = 92.3 MHz (mega hertz)
2. KSHE-94.7 : Frequency = 94.7 MHz
The wavelength (λ) and frequency (ν) are related as:
ν = c/λ ------(1)
Energy (E), frequency (ν) and wavelength (λ) are related as:
E = hν -----(2)
(or)
E = hc/λ ----(3)
A) Based on equation (2), higher the frequency higher is the energy. Therefore, station KSHE broadcasts waves with higher energy
B) Based on equation (1), higher the frequency lower will be the wavelength. Station KSHE will broadcast waves with shorter wavelength
C) KSHE will broadcast waves with higher frequency
Answer:
![C_{6} H_{6}](https://tex.z-dn.net/?f=C_%7B6%7D%20H_%7B6%7D)
Explanation:
First, find the mass of empirical formula, CH. 12.01 g/mol is for carbon, and 1.008 g/mol is for hydrogen. 12.01+1.008=13.018 G/mol CH. Divide 78.110 G/mol by 13.018 g/mol. You get approximately 6. Multiply that by the subscript of each element. 6(CH)=
![C_{6} H_{6}](https://tex.z-dn.net/?f=C_%7B6%7D%20H_%7B6%7D)