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IrinaVladis [17]
4 years ago
13

PLEASE HELP :-)

Chemistry
1 answer:
timofeeve [1]4 years ago
8 0
We can solve this problem using the long hand solution, wherein we 1 by 1 analyze the different equilibrium reactions or by simply using the Henderson Hasselbach equation. The equation is 

pH = -log(pKa) + log (salt/acid)

since the acid and the salt have the same concentration, the log (salt/acid) term is equal to zero. 

thus 

pH = -log(1.73*10-5)
pH = 4.76

please be careful with the negative sign 

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Alex787 [66]

Answer:

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Explanation:

6 0
3 years ago
1. Naturally occurring europium (Eu) consists of two isotopes was a mass of 151 and 153. Europium- 151 has an abundance of 48.03
sergejj [24]
The atomic mass of Europium is 152 amu

Work:
151(0.4803) = 72.52 amu
153(0.5197) = 79.5 amu
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Enter the electron configuration for I+ using noble gas shorthand notation.
Maurinko [17]

Answer:

[Kr] 4d10 5s2 5p4

Explanation:

The Symbol I represents Iodine. It has atomic number of 53. The full electronic configuration is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5

However the question requested for the configuration of I+.

I+ is a cation and it simply refers to an iodine atom that has lost a single electron. The electronic configuration of I+ is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4

Using Noble gas shorthand representation, we have;

[Kr] 4d10 5s2 5p4

6 0
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Hexane is a common laboratory solvent and a component of petrol. Its combustion reaction is as follows: 2 C6H14 (9) + 19 02(9) +
Flauer [41]

Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is, 1.01\times 10^3

Explanation :

The given balanced reaction is,

2C_6H_{14}(g)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(l)

Given:

Moles of hexane = 0.121 mol

\Delta H = -8326 kJ/mol

The negative sign indicate that the reaction exothermic or amount of heat released.

As, 1 mole of hexane released heat = 8326 kJ

So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈ 1.01\times 10^3kJ

Therefore, the heat released by the combustion of 1.121 mol of hexane is 1.01\times 10^3kJ.

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4 years ago
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Website:kidshealth.org
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3 years ago
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