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DanielleElmas [232]
2 years ago
12

Enter the electron configuration for I+ using noble gas shorthand notation.

Chemistry
1 answer:
Maurinko [17]2 years ago
6 0

Answer:

[Kr] 4d10 5s2 5p4

Explanation:

The Symbol I represents Iodine. It has atomic number of 53. The full electronic configuration is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5

However the question requested for the configuration of I+.

I+ is a cation and it simply refers to an iodine atom that has lost a single electron. The electronic configuration of I+ is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4

Using Noble gas shorthand representation, we have;

[Kr] 4d10 5s2 5p4

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For each of the following compounds, identify what type of bonding holds them together.
svet-max [94.6K]

Explanation

NaCl:  Ionic crystal lattice forces

Hg:   Metallic bonding

CO₂:  London dispersion forces

CH₄:  London dispersion forces

Li₂O:  Ionic crystal lattice forces

Ag:  Metallic bonds

Ionic crystal lattice forces are strong electrostatic force of attraction between oppositely charged ions arranged into a crystal lattice of ionic compound. NaCl and Li₂O are ionic compounds

London dispersion forces holds the molecules of carbon dioxide and methane. They are weak attractions found between non-polar (and polar) molecules.

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4 0
3 years ago
Which of the following statements is true?
zalisa [80]
It's A, t<span>The figure is a molecule and an element.</span>
6 0
2 years ago
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I don’t know how to solve this
stepladder [879]
Hi,

Answer is 191.2.

800J = 191.2 cal

Hope this helps.
7 0
3 years ago
A solution of LiCl in water has XLiCl = 0.0800. What is the molality? A solution of LiCl in water has XLiCl = 0.0800. What is th
Kay [80]

Answer:

mol LiCl = 4.83 m

Explanation:

GIven:

Solution of LiCl in water XLiCl = 0.0800

Mol of water in kg = 55.55 mole

Find:

Molality

Computation:

mole fraction = mol LiCl / (mol water + mol LiCl)

0.0800 = mol LiCl / (55.55 mol + mol LiCl)

0.0800 mol LiCl + 4.444 mol = mol LiCl

mol LiCl - 0.0800 mol LiCl = 4.444 mol

0.92 mol LiCl = 4.444 mol

mol LiCl = 4.83 m

7 0
3 years ago
During oxidation of ethanol to ethanol, the ethanol formed was found to be contaminated with unconverted ethanol, describe how y
Dafna1 [17]

<u><em>The process of how we would obtain </em></u><u><em>ethanal</em></u><u><em> </em></u><u><em>free</em></u><u><em> from ethanol is described in the explanations below. </em></u>

<u><em /></u>

  • In Chemistry, Ethanol undergoes oxidation in the presence of sodium dichromate plus sulphuric acid to yield ethanal and water.

The procedure for achieving this in the laboratory is as follows;

  • Step 1; Measure a quantity of a solution of sodium dichromate acidified in a dilute sulphuric acid and pour into a test tube.

  • Step 2; Add excess <em>ethanol</em>. This is because if we don't do so there will be plenty of oxidizing agent to carry out a second operation which changes the aldehyde to ethanoic acid. However, we need only the aldehyde.

  • Step 3; When the aldehyde ethanal begins to form which will be evident by the change in the colour of solution from <em>orange to green</em>, then the mixture should be distilled from the test tube and tbethe aldehyde collevted so that it doesn't undergo additional oxidation into ethanoic acid.

Read more at; https://brainly.in/question/18574624

4 0
2 years ago
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