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3 years ago

Subtract the equations. 5x + 4y = 25 (5x +2y= 3)

Mathematics

1 answer:

pychu [463]3 years ago

8 0

Answer: x=3 y=6

Step-by-step explanation:

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paul deposited 1,200$ into an account that earns 1.5% in annual simple interest. If paul does not make any deposites or withdraw

aliina [53]

1236.27 is the correct answer

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3 years ago

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Solving 8 problems per minute, Fast Finn can finish his test in time. He was however, working faster, solving 10 problems per mi

mrs_skeptik [129]

Answer:

Number of problems = 240

Step-by-step explanation:

Let x be the number of questions and t be the time.

Given:

Average rate = 8 problems per minute

Fast Finn rate = 10 problems per minute

Fast Finn taken time = t - 6

We need to find the number of problems on the test paper.

Solution:

Average rate to solve test paper.

$Average\ rate =\frac{Number\ of\ questions}{time}$

$8 =\frac{x}{t}$

$t =\frac{x}{8}$ --------------(1)

Fast Finn rate to solve the test paper.

$Average\ rate =\frac{Number\ of\ questions}{time}$

$10 =\frac{x}{t-6}$

Using cross multiplication rule.

$x=10(t-6)$

$x=10t-60$

substitute $t =\frac{x}{8}$ from equation 1.

$x=10(\frac{x}{8}) -60$

Rearrange the equation as:

$x - \frac{5}{4}x = -60$

$\frac{4x-5x}{4}=-60$

$-\frac{x}{4} = -60$

Using cross multiplication rule.

$x = 60\times 4$

x = 240 problems.

Therefore, 240 problems were on the test.

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3 years ago

Whats 45 572 in words

Leona [35]

That is:
Forty-five thousand, five hundred seventy-two.
~Deceptiøn

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3 years ago

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Find the value of the following expression: (2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whol

koban [17]

Answer:

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

Step-by-step explanation:

$\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228$

$=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}$

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

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3 years ago

Select all of the products of 2.74 • 7.5

Nana76 [90]

2.74x7.5=20.55=20.550
That's all of your answers.

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3 years ago

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