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3 years ago

Solve for z. z−4/9−1/3=5/9

Mathematics

2 answers:

uysha [10]3 years ago

7 0

Answer: The required value of z is $\dfrac{4}{3}.$

Step-by-step explanation: We are given to solve the following equation for z :

$z-\dfrac{4}{9}-\dfrac{1}{3}=\dfrac{5}{9}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To solve the given equation for z, we need to take all the constant terms on the right-hand side of the equation.

From equation (i), we have

$z-\dfrac{4}{9}-\dfrac{1}{3}=\dfrac{5}{9}\\\\\\\Rightarrow z=\dfrac{5}{9}+\dfrac{1}{3}+\dfrac{4}{9}\\\\\\\Rightarrow z=\dfrac{5+3+4}{9}\\\\\\\Rightarrow z=\dfrac{12}{9}\\\\\Rightarrow z=\dfrac{4}{3}.$

Thus, the required value of z is $\dfrac{4}{3}.$

laila [671]3 years ago

4 0

Z-4/9-1/3=5/9
z-4 =5/9(9-1/3)

z-4 =4.414814815

z =8.814

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Step-by-step explanation:

1) Here total number of letters = 10

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3 years ago

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√36x

All under the radical

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3 years ago

A landscaping company placed two orders with a nursery. First order was 5 bushes and 8 trees,and totaled $374.The second order w

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

azamat

Answer:

Maximum at points (8,0),(-8,0).Minimum at points (0,8), (0,-8).

Step-by-step explanation:

There are multiple ways of using lagrange multipliers. Most of them are equivalent.

Consider the function $F(x,y) = x^2-y^2-\lambda(x^2+y^2-64)$ . We want the following $\frac{\partial F}{\partial x} = \frac{\partial F}{\partial y} = \frac{\partial F}{\partial \lambda} = 0$ .

Then, we have

$\frac{\partial F}{\partial x} = 2x-2x\lambda= 2x(1-\lambda)=0$

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3 years ago