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mina [271]
3 years ago
10

5 kilo meters = ___________meters

Physics
1 answer:
DiKsa [7]3 years ago
4 0

Answer:

5,000 meters

Explanation:

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If a car driving down the road doubles its speed what happens to its kinetic energy?
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Two objects are dropped from rest from the same height. Object A falls through a distance during a time t, and object B falls th
UNO [17]

Answer:

Distance covered by B is 4 times distance covered by A

Explanation:

For an object in free fall starting from rest, the distance covered by the object in a time t is

s=\frac{1}{2}gt^2

where

s is the distance covered

g is the acceleration due to gravity

t is the time elapsed

In this problem:

- Object A falls through a distance s_A during a time t, so the distance covered by object A is

s_A=\frac{1}{2}gt^2

- Object B falls through a distance s_B during a time 2t, so the distance covered by object B is

s_B=\frac{1}{2}g(2t)^2 = 4(\frac{1}{2}gt^2)=4s_A

So, the distance covered by object B is 4 times the distance covered by object A.

5 0
3 years ago
If it requires 2.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re
valina [46]

Answer:

16 J

Explanation:

It is given that,

Work done, W = 2 J

A spring is stretched by 2.0 cm from its equilibrium length

We need to find how much more work will be required to stretch it an additional 4.0 cm.

Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :

U=\dfrac{1}{2}kx^2\\\\k=\dfrac{2U}{x^2}\\\\k=\dfrac{2(2)}{(0.02)^2}\\\\k=10000\ N/m

The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.

W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 10000\times ((0.06)^2-(0.02)^2)\\\\W=16\ J

So, the required work done is 16 J.

7 0
3 years ago
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