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10 months ago

15

There is a filing cabinent that is 52 in. tall and 15 in. wide. The center of gravity of the cabinet is right at the center. To

what angle can the cabinet be tipped before it falls over?

1 answer:

erastova [34]10 months ago

5 0

Answer:

16 degrees

Explanation:

The tipping point of the cabinet is sketched below.

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A vehicle moves in a straight line with an

nordsb [41]

The solution to your problem is as follows:

<span>5km/h2 x 1 h/60 min x 1 min/60 sec x 1000m/km = 1.39 meters per second change each second.
</span>
Therefore, the speed change each second is <span>1.39 meters per second change each second.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>

7 0

2 years ago

A 5kg box slides across the floor with an initial velocity of 5m/s. If the coefficient of kinetic friction between the box and t

4vir4ik [10]

The net force on the block perpendicular to the floor is

∑ F[perp] = F[normal] - mg = 0

so that

F[normal] = (5 kg) g = 49 N

Then

F[friction] = 0.1 F[normal] = 4.9 N

so that the net force parallel to the floor is

∑ F[para] = -4.9 N = (5 kg) a

Solve for the acceleration a :

a = (-4.9 N) / (5 kg) = -0.98 m/s²

Starting with an initial velocity of 5 m/s, the box comes to a stop after time t such that

0 = 5 m/s - (0.98 m/s²) t

⇒ t ≈ 5.1 s

5 0

1 year ago

An aluminum cup contains 225 g of water and a 40-g copper stirrer, all at 27Â°C. A 470-g sample of silver at an initial temperat

vagabundo [1.1K]

Answer:

Mal = 0.232 kg = 232 g

Explanation:

mass of water (Mw) = 225 g = 0.225 kg

mass of copper stirrer (Mcu) = 40 g = 0.04 kg

initial temperature of water (Tw) = 27 degrees

mass of silver (Mag) = 470 g = 0.47 kg

initial temperature of silver (Ts) = 85 degrees

final temperature of the mixture (T) = 32 degrees

find the mass of the aluminum cup (Mal)

applying the conservation of energy

((Mal.cAl) + (Mw.cW) + (Mcu.cCu))(ΔTw) = (Mag.cAg)(ΔTag)

we require the specific heat capacities of water (cW) , aluminium (cAl) , copper (cCu) and silver (cAg) which are as follows

water (cW) =4186 J/kg.K

aluminium (cAl) = 900 J/kg.K

copper (cCu) = 387 J/kg.K

silver (cAg) = 234 J/kg.K

now we can put in our values to get the mass of the Aluminium cup (Mag)

((Mal.900) + (0.225 x 4186) + (0.04 x 387))(32-27) = (0.47 x 234)(85-32)

(900 . Mal + 957.33) x 5 = 5828.94

900 .Mal + 957.33 = 1165.79

900.Mal = 1165.79 - 957.33 = 208.5

Mal = 0.232 kg = 232 g

8 0

2 years ago

A constant net force of 20 N is applied to a 32kg car, causing it to speed up from 4.0 to 9.0 m/s. How long is the force applied

pishuonlain [190]

Answer:

8 seconds

Explanation:

From Newton's second law;

Ft = m(v-u)

F = Force applied

t = time taken

v = final velocity

u = initial velocity

20 * t = 32 (9 - 4)

20t = 32 * 5

t = 32 * 5/ 20

t = 8 seconds

8 0

2 years ago

Time measurements from a stopwatch are not precise. Why not ?

fgiga [73]

Human error (average human reaction time is .2 seconds)

5 0

2 years ago